Physics-
General
Easy
Question
Two identical capacitors 1 and 2 are connected in series. The capacitor 2 contains a dielectric slab of constant K as shown. They are connected to a battery of emf V0 volts. The dielectric slab is then removed. Let Q1 and Q2 be the charge stored in the capacitors before removing the slab and Q1¢, and Q2¢ be the values after removing the slab. Then
Q 1 = K + 1 K 
Q 2 = ( K + 1 ) 2 
Q 2 = K + 1 2 K 
Q 1 = K 2
The correct answer is:
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