Physics-
General
Easy
Question
Two rectangular blocks 
and 
of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8 
and are placed on a frictionless horizontal surface. The block was given an initial velocity of 0.15 
in the direction shown in the figure. The maximum compression of the spring during the motion is
- 0.01 m
- 0.02 m
- 0.05 m
- 0.03 m
The correct answer is: 0.05 m
As the block A moves with velocity with velocity 0.15 , it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15 . Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.
According to the law of conservation of linear momentum, we get
Or 
According to the law of conservation of energy
Or 
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