Physics-
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Question

When an AC source of emf E equals E subscript 0 end subscript s i n invisible function application left parenthesis 100 t right parenthesis is connected across a circuit, the phase difference between the E and the current i in the circuit is observed to be pi divided by 4 , as shown in the diagram. If the circuit consists possibly only of R-C or R-L or L-C series, find the relationship between the two elements.

  1. R equals 1 k capital omega comma C equals 10 mu F    
  2. R equals 1 k capital omega comma C equals 1 mu F    
  3. R equals 1 k capital omega comma L equals 10 H    
  4. R equals 1 k capital omega comma L equals 1 H    

The correct answer is: R equals 1 k capital omega comma C equals 10 mu F


    Current leads emf so circuit is R – C.
    table row cell t a n invisible function application ϕ equals x subscript L end subscript divided by R comma ϕ equals 45 to the power of ring operator end exponent comma R equals 1000 capital omega comma omega equals 100 end cell row cell text end text text s end text text i end text text n end text text c end text text e end text text end text t a n invisible function application 45 to the power of ring operator end exponent equals fraction numerator 1 over denominator o C R end fraction text end text text S end text text o end text text end text C equals 10 mu F end cell end table

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