science
Grade-11
Easy
Question
i^.i^=
- j^
- i^
- k^
- 1
Hint:
- a · b = |a| × |b| × cos(θ)
The correct answer is: 1
- a · b = |a| × |b| × cos(θ)
- Where:
|a| is the magnitude (length) of vector a.
|b| is the magnitude (length) of vector b.
θ is the angle between a and b.
- here, a= i^ so |a|=1 ,b=i^ so |b|=1
- Also, θ is angle between two vectors but here both vector are same that is i^ so angle is zero.
- cos(0)=1
- so i^.i^=1.1.cos(0)=1
|a| is the magnitude (length) of vector a.
|b| is the magnitude (length) of vector b.
θ is the angle between a and b.
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