science
Grade-11
Easy
Question
Let us consider two cars, A and B, are moving with a constant acceleration of 2 m/ s2 and a constant velocity of 3 m/s with t=0 s. Bo the cars are 12 m apart, car A is behind car B. Find the time when car A overtakes car B.
- 4
- 3
- 2
- 1
Hint:
- Use Equation Of motion
- The distance covered by car A - 12 meter = Distance covered by Car B.
The correct answer is: 4
- Given that Car A is moving with acceleration 2 m/s^2 with no initial velocity
- Car B is moving with Constant 3 m/s
- The Distance covered by each car is equal during the instant of Overtaking.
- By the equation of motion ut+1/2at^2 = ut + 12
0xt + 1/2(2)t2 = 3t + 12
- By the solving the quadratic equation we get t = 4 seconds.
0xt + 1/2(2)t2 = 3t + 12
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