Maths-
General
Easy
Question
Simplify:
41/3 (21/3 × 31/2) ÷ 91/4
The correct answer is: Simplifying the given expression, we get- 2.
Hint:-
In Mathematics, lets say, "a" represents a number and "n" is the number of times that number is to be multiplied with itself, in order to get a desired result. Then, such result can be written as an, where a is called the base and n is its power/ exponent.
an = a × a × ... × a n times.
Step-by-step solution:-
41/3 (21/3 × 31/2) ÷ 91/4
= (22)1/3 (21/3 × 31/2) × 1/(32)1/4 …......................................................... (Taking reciprocal)
= 22/3 × 21/3 × 31/2 × 1/32/4 …................................................................ [(bn)m = bnm]
= 22/3 × 21/3 × 31/2 × 1/31/2
= 22/3+1/3 × 31/2-1/2 ............................................................................... (an *⋅am = an+m & an/am = an-m)
= 21 × 30
= 2 × 1 ................................................................................................. (b1 = b & b0 = 1)
= 2.
Final Answer:-
∴ Simplifying the given expression, we get- 2.
Related Questions to study
Maths-
Simplify:
(64 / 125)−2/3 ÷ (625 / 256)1/4 × (−6)0
Simplify:
(64 / 125)−2/3 ÷ (625 / 256)1/4 × (−6)0
Maths-General
Maths-
Solve for x-
(3/5)(x+1)/3 = 625 / 81
Solve for x-
(3/5)(x+1)/3 = 625 / 81
Maths-General
Maths-
Solve for x-
(3/7)(1−2x)/2 = 12 19/27
Solve for x-
(3/7)(1−2x)/2 = 12 19/27
Maths-General
Maths-
The floor of a study room is in the shape of a rectangle, it is 12 ft long and 10 ft wide. How many tiles with 2 ft × 2 ft are required to cover the floor of the room?
The floor of a study room is in the shape of a rectangle, it is 12 ft long and 10 ft wide. How many tiles with 2 ft × 2 ft are required to cover the floor of the room?
Maths-General
Maths-
Solve for x∶
8 × 22x + 4 × 2x+1 = 1 + 2x
Solve for x∶
8 × 22x + 4 × 2x+1 = 1 + 2x
Maths-General
Maths-
The perimeter of a rectangle is 30 cm. The length and breadth of the rectangle are integers in cm. Find the number of possible pairs of length and breadth in cm.
The perimeter of a rectangle is 30 cm. The length and breadth of the rectangle are integers in cm. Find the number of possible pairs of length and breadth in cm.
Maths-General
Maths-
Identify the correct congruence statement
Identify the correct congruence statement
Maths-General
Maths-
Find the area and the perimeter of a square room , the length of whose diagonal is 15 cm . Give your answer to three significant figures.
Find the area and the perimeter of a square room , the length of whose diagonal is 15 cm . Give your answer to three significant figures.
Maths-General
Maths-
The identical rectangles of dimensions 12 cm x10 cm are overlapping. The over lapped part is a square of side 2 cm. Find the area of it.
The identical rectangles of dimensions 12 cm x10 cm are overlapping. The over lapped part is a square of side 2 cm. Find the area of it.
Maths-General
Maths-
Solve for x & y:
7x - y = 49 ,7x + y = 343
Solve for x & y:
7x - y = 49 ,7x + y = 343
Maths-General
Maths-
A table cover of 4 m x 2m is spread on a meeting table. If 25 cm table cover is hanging all around the table. Find the cost of polishing the table top at Rs 2.25 per sq.metre.
A table cover of 4 m x 2m is spread on a meeting table. If 25 cm table cover is hanging all around the table. Find the cost of polishing the table top at Rs 2.25 per sq.metre.
Maths-General
Maths-
A rectangle of perimeter 276 cm is cut into five equal squares. Find the area of each square.
A rectangle of perimeter 276 cm is cut into five equal squares. Find the area of each square.
Maths-General
Maths-
Simplify:
(1/4)−2 − 3 (8)2/3 (40) + (9/16)−1/2
Simplify:
(1/4)−2 − 3 (8)2/3 (40) + (9/16)−1/2
Maths-General
Maths-
A path of uniform width of 5 m runs around outside a rectangular field 30 m by 25 m.Find the area of the path.
A path of uniform width of 5 m runs around outside a rectangular field 30 m by 25 m.Find the area of the path.
Maths-General
Maths-
The area of a square field is 49 m. How many times kavya has to run has to run around it to cover 224 m.
The area of a square field is 49 m. How many times kavya has to run has to run around it to cover 224 m.
Maths-General