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Maths-

General

Easy

Question

$tan space open parentheses pi over 4 plus x over 2 close parentheses minus tan space open parentheses pi over 4 minus x over 2 close parentheses equals 2$ then the general solution of $x$ =

$n π \pm \frac{π}{4}, \forall n \in Z$
$n π + \frac{π}{4}, \forall n \in Z$
$n π - \frac{π}{4}, \forall n \in Z$
$n π, \forall n \in Z$

The correct answer is: $n pi plus pi over 4 comma straight for all n element of Z$

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