Physics-
General
Easy

Question

The angular velocity and the amplitude of a simple pendulum is  and a respectively. At a displacement  from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is

  1. open parentheses a squared minus x squared omega squared close parentheses divided by x squared omega squared
  2. x squared omega squared divided by open parentheses a squared minus x squared omega squared close parentheses
  3. x squared divided by open parentheses a squared minus x squared close parentheses
  4. x squared divided by open parentheses a squared minus x squared close parentheses

The correct answer is: x squared divided by open parentheses a squared minus x squared close parentheses


    PE comma straight V equals 1 half straight m omega squared straight x squared
    and KE comma straight T equals 1 half straight m omega squared open parentheses straight a squared minus straight x squared close parentheses
    therefore straight T over straight V equals fraction numerator straight a squared minus straight x squared over denominator straight x squared end fraction

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