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General

General

Easy

Question

The Complete set of values of 'x' which satisfy the inequations: $5 x plus 2 less than 3 x plus 8 space a n d space fraction numerator x plus 2 over denominator x minus 1 end fraction less than 4 space i s$

$(- \infty, 1)$
(2, 3)
$(- \infty, 3)$
$(- \infty, 1) \cup (2, 3)$

The correct answer is: $left parenthesis negative infinity comma space 1 right parenthesis space union space left parenthesis 2 comma space 3 right parenthesis$

Related Questions to study

The interval in which $fraction numerator x squared plus 2 x plus 3 over denominator x squared minus 3 x plus 2 end fraction$ is positive is

The interval in which $fraction numerator x squared plus 2 x plus 3 over denominator x squared minus 3 x plus 2 end fraction$ is positive is

Rr (sin A + sin B + sin C) =

Rr (sin A + sin B + sin C) =

r1+ r2 =

r1+ r2 =

parallel

$fraction numerator r subscript 1 end subscript over denominator b c end fraction$ + $fraction numerator r subscript 2 end subscript over denominator c a end fraction$ + $fraction numerator r subscript 3 end subscript over denominator a b end fraction$ =

$fraction numerator r subscript 1 end subscript over denominator b c end fraction$ + $fraction numerator r subscript 2 end subscript over denominator c a end fraction$ + $fraction numerator r subscript 3 end subscript over denominator a b end fraction$ =

If a , b, c are in A.P., then r1, r2, r3 are in

If a , b, c are in A.P., then r1, r2, r3 are in

If the sides be a, b, c then (r1–r) (r2+ r3) =

If the sides be a, b, c then (r1–r) (r2+ r3) =

parallel

If the sides be a, b, c then $fraction numerator b minus c over denominator r subscript 1 end subscript end fraction$ + $fraction numerator c minus a over denominator r subscript 2 end subscript end fraction$ + $fraction numerator a minus b over denominator r subscript 3 end subscript end fraction$ =

If the sides be a, b, c then $fraction numerator b minus c over denominator r subscript 1 end subscript end fraction$ + $fraction numerator c minus a over denominator r subscript 2 end subscript end fraction$ + $fraction numerator a minus b over denominator r subscript 3 end subscript end fraction$ =

If the sides be a, b, c then (r + r1) tan $fraction numerator B minus C over denominator 2 end fraction$ +(r + r2) tan $fraction numerator C minus A over denominator 2 end fraction$ + (r+ r3) tan $fraction numerator A minus B over denominator 2 end fraction$ =

If the sides be a, b, c then (r + r1) tan $fraction numerator B minus C over denominator 2 end fraction$ +(r + r2) tan $fraction numerator C minus A over denominator 2 end fraction$ + (r+ r3) tan $fraction numerator A minus B over denominator 2 end fraction$ =

$open parentheses fraction numerator 1 over denominator r subscript 1 end subscript end fraction plus fraction numerator 1 over denominator r subscript 2 end subscript end fraction close parentheses$ $open parentheses fraction numerator 1 over denominator r subscript 3 end subscript end fraction plus fraction numerator 1 over denominator r subscript 1 end subscript end fraction close parentheses$ =

$open parentheses fraction numerator 1 over denominator r subscript 1 end subscript end fraction plus fraction numerator 1 over denominator r subscript 2 end subscript end fraction close parentheses$ $open parentheses fraction numerator 1 over denominator r subscript 3 end subscript end fraction plus fraction numerator 1 over denominator r subscript 1 end subscript end fraction close parentheses$ =

parallel

$I f space fraction numerator left parenthesis x minus 2 right parenthesis left parenthesis 1 minus x right parenthesis left parenthesis x minus 3 right parenthesis cubed left parenthesis x minus 4 right parenthesis squared over denominator left parenthesis x plus 1 right parenthesis end fraction less or equal than 0 space t h e n space x space l i e s space i n$

$I f space fraction numerator left parenthesis x minus 2 right parenthesis left parenthesis 1 minus x right parenthesis left parenthesis x minus 3 right parenthesis cubed left parenthesis x minus 4 right parenthesis squared over denominator left parenthesis x plus 1 right parenthesis end fraction less or equal than 0 space t h e n space x space l i e s space i n$

(r1 – r) (r2 – r) (r3 – r) =

(r1 – r) (r2 – r) (r3 – r) =

$fraction numerator 1 over denominator r subscript 1 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 2 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 3 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript blank superscript 2 end superscript end fraction$ =

$fraction numerator 1 over denominator r subscript 1 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 2 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript 3 end subscript superscript 2 end superscript end fraction$ + $fraction numerator 1 over denominator r subscript blank superscript 2 end superscript end fraction$ =

parallel

$I f space fraction numerator left parenthesis 2 x minus 1 right parenthesis left parenthesis x minus 1 right parenthesis squared left parenthesis x minus 2 right parenthesis cubed over denominator left parenthesis x minus 4 right parenthesis to the power of 4 end fraction greater than 0 space t h e n space x space l i e s space i n$

$I f space fraction numerator left parenthesis 2 x minus 1 right parenthesis left parenthesis x minus 1 right parenthesis squared left parenthesis x minus 2 right parenthesis cubed over denominator left parenthesis x minus 4 right parenthesis to the power of 4 end fraction greater than 0 space t h e n space x space l i e s space i n$

$i f space fraction numerator open parentheses x squared plus 3 close parentheses open parentheses x minus 1 close parentheses to the power of 4 over denominator open parentheses x plus 1 close parentheses end fraction greater than 0 space t h e n space x element of$

$i f space fraction numerator open parentheses x squared plus 3 close parentheses open parentheses x minus 1 close parentheses to the power of 4 over denominator open parentheses x plus 1 close parentheses end fraction greater than 0 space t h e n space x element of$

If (a – b) (s – c) = (b – c) (s – a) then r1, r2, r3 are in -

If (a – b) (s – c) = (b – c) (s – a) then r1, r2, r3 are in -

parallel

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