Maths-
General
Easy

Question

The lines fraction numerator x minus 3 over denominator 2 end fraction equals fraction numerator y minus 2 over denominator 3 end fraction equals fraction numerator z minus 1 over denominator lambda end fraction and fraction numerator straight x minus 2 over denominator 3 end fraction equals fraction numerator straight y minus 3 over denominator 2 end fraction equals fraction numerator straight z minus 2 over denominator 3 end fraction lie in a same plane. Based on this information answer the following. Point of intersection of these lines is

  1. (3,5,7)
  2. (5,2,5)
  3. (5,5,5)
  4. None

The correct answer is: (5,5,5)

Related Questions to study

General
chemistry-

The given pair is :

The given pair is :

chemistry-General
General
chemistry-

Number of stereo centre and stereoisomer of the given compound :

Number of stereo centre and stereoisomer of the given compound :

chemistry-General
General
chemistry-

The structures A and B represent :

The structures A and B represent :

chemistry-General
parallel
General
chemistry-

Write the order of basic strength :

Write the order of basic strength :

chemistry-General
General
chemistry-

Arrange the following acids in decreasing order of acidity :

Arrange the following acids in decreasing order of acidity :

chemistry-General
General
maths-

The lines fraction numerator x minus 3 over denominator 2 end fraction equals fraction numerator y minus 2 over denominator 3 end fraction equals fraction numerator z minus 1 over denominator lambda end fraction and fraction numerator x minus 2 over denominator 3 end fraction equals fraction numerator y minus 3 over denominator 2 end fraction equals fraction numerator z minus 2 over denominator 3 end fraction lie in a same plane. Based on this information answer the following. The value of lambda is

The lines fraction numerator x minus 3 over denominator 2 end fraction equals fraction numerator y minus 2 over denominator 3 end fraction equals fraction numerator z minus 1 over denominator lambda end fraction and fraction numerator x minus 2 over denominator 3 end fraction equals fraction numerator y minus 3 over denominator 2 end fraction equals fraction numerator z minus 2 over denominator 3 end fraction lie in a same plane. Based on this information answer the following. The value of lambda is

maths-General
parallel
General
maths-

Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Equation of the plane containing the triangle ABC is

Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Equation of the plane containing the triangle ABC is

maths-General
General
maths-

Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Projection of AB on BC is

Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Projection of AB on BC is

maths-General
General
maths-

Let A(2,3,5), B(-1,3,2),  are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following The value of  is equal to

Let A(2,3,5), B(-1,3,2),  are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following The value of  is equal to

maths-General
parallel
General
Maths-

Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The image of plane P1 in the plane mirror P2 is

 Therefore, the equation becomes 7x-y+2z=9.

Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The image of plane P1 in the plane mirror P2 is

Maths-General

 Therefore, the equation becomes 7x-y+2z=9.

General
Maths-

Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The equation of the bisector of angle of the planes P1 and P2 which not containing origin is

P subscript 1 colon 2 x minus y plus z equals 2 + P subscript 2 colon x plus 2 y minus z equals 3
-> 3x +y = 5.

Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The equation of the bisector of angle of the planes P1 and P2 which not containing origin is

Maths-General

P subscript 1 colon 2 x minus y plus z equals 2 + P subscript 2 colon x plus 2 y minus z equals 3
-> 3x +y = 5.

General
maths-

Let f left parenthesis x right parenthesis equals sin invisible function application x integral subscript 1 superscript x   cos invisible function application t d t plus 2 integral subscript 0 superscript x   t d t plus cos squared invisible function application x minus x squared then area bounded by x. f(x), and x=0, x=5 with x axis, is (in sq units)

Let f left parenthesis x right parenthesis equals sin invisible function application x integral subscript 1 superscript x   cos invisible function application t d t plus 2 integral subscript 0 superscript x   t d t plus cos squared invisible function application x minus x squared then area bounded by x. f(x), and x=0, x=5 with x axis, is (in sq units)

maths-General
parallel
General
maths-

(6,6) is a point on the circle x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 6 y minus 12 equals 0 by translation of origin to a certain point the translated equation is x to the power of 2 end exponent plus y to the power of 2 end exponent equals 25 the new co-ordinates of (6,6) are

(6,6) is a point on the circle x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 6 y minus 12 equals 0 by translation of origin to a certain point the translated equation is x to the power of 2 end exponent plus y to the power of 2 end exponent equals 25 the new co-ordinates of (6,6) are

maths-General
General
maths-

The locus of points from which lengths of tangents to the two circles x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x plus 3 equals 0 comma x squared plus y squared minus 6 x plus 5 equals 0 are in the ratio 2 : 3 is a circle with centre

The locus of points from which lengths of tangents to the two circles x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x plus 3 equals 0 comma x squared plus y squared minus 6 x plus 5 equals 0 are in the ratio 2 : 3 is a circle with centre

maths-General
General
chemistry-

A gas is found to have a density of 1.80 g L to the power of negative 1 end exponent at 760 mm pressure and 27ºC. The gas will be

A gas is found to have a density of 1.80 g L to the power of negative 1 end exponent at 760 mm pressure and 27ºC. The gas will be

chemistry-General
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.