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General

General

Easy

Question

The primary sex organs in males and females respectively are

Testis and ovary
Penis and vagina
Scrotum and mammary gland
Testis and uterus

The correct answer is: Testis and ovary

Related Questions to study

The first meiotic division during oogenesis is completed at the stage of

The first meiotic division during oogenesis is completed at the stage of

If $fraction numerator left parenthesis x squared plus 3 right parenthesis left parenthesis x minus 1 right parenthesis to the power of 4 over denominator left parenthesis x plus 1 right parenthesis end fraction greater than 0 space t h e n space x element of$

If $fraction numerator left parenthesis x squared plus 3 right parenthesis left parenthesis x minus 1 right parenthesis to the power of 4 over denominator left parenthesis x plus 1 right parenthesis end fraction greater than 0 space t h e n space x element of$

Assertion : In any ABC, minimum value of $fraction numerator r subscript 1 end subscript plus r subscript 2 end subscript plus r subscript 3 end subscript over denominator r end fraction$ is 9.
Reason : A.M.  G.M.

Assertion : In any ABC, minimum value of $fraction numerator r subscript 1 end subscript plus r subscript 2 end subscript plus r subscript 3 end subscript over denominator r end fraction$ is 9.
Reason : A.M.  G.M.

parallel

Assertion: The orthocentre of the given triangle is coincident with the in-centre of the pedal triangle of the given triangle.
Reason : Pedal triangle is the ex-central triangle of the given triangle.

Assertion: The orthocentre of the given triangle is coincident with the in-centre of the pedal triangle of the given triangle.
Reason : Pedal triangle is the ex-central triangle of the given triangle.

A large number of primary follicles degenerate during the phase from birth to puberty. Therefore at puberty each ovary has about

A large number of primary follicles degenerate during the phase from birth to puberty. Therefore at puberty each ovary has about

Assertion : The side of regular hexagon is 5 cm whose radius of inscribed circle is 5cm.
Reason : The radius of inscribed circle of a regular polygon of side a is $fraction numerator a over denominator 2 end fraction cot invisible function application open parentheses fraction numerator pi over denominator n end fraction close parentheses$ .

Assertion : The side of regular hexagon is 5 cm whose radius of inscribed circle is 5cm.
Reason : The radius of inscribed circle of a regular polygon of side a is $fraction numerator a over denominator 2 end fraction cot invisible function application open parentheses fraction numerator pi over denominator n end fraction close parentheses$ .

parallel

Assertion : In a ABC, $fraction numerator a cos invisible function application A plus b cos invisible function application B plus c cos invisible function application C over denominator a plus b plus c end fraction$ is equal to $fraction numerator r over denominator R end fraction$
Reason : In equilateral triangle the ratio between In-radius and circum-radius is 1 : 2.

Assertion : In a ABC, $fraction numerator a cos invisible function application A plus b cos invisible function application B plus c cos invisible function application C over denominator a plus b plus c end fraction$ is equal to $fraction numerator r over denominator R end fraction$
Reason : In equilateral triangle the ratio between In-radius and circum-radius is 1 : 2.

Assertion : In any triangle ABC, $fraction numerator 1 over denominator a b end fraction plus fraction numerator 1 over denominator b c end fraction plus fraction numerator 1 over denominator c a end fraction equals fraction numerator 1 over denominator 2 r R end fraction$ , where r is in radius and R is circum radius.
Reason : R  2r.

Assertion : In any triangle ABC, $fraction numerator 1 over denominator a b end fraction plus fraction numerator 1 over denominator b c end fraction plus fraction numerator 1 over denominator c a end fraction equals fraction numerator 1 over denominator 2 r R end fraction$ , where r is in radius and R is circum radius.
Reason : R  2r.

In any equilateral , three circles of radii one are touching to the sides given as in the figure then area of the 

In any equilateral , three circles of radii one are touching to the sides given as in the figure then area of the 
Maths-General

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If the sides a, b, c of a triangle are such that a : b : c : : 1 : $square root of 3$ : 2, then the A : B : C is -

If the sides a, b, c of a triangle are such that a : b : c : : 1 : $square root of 3$ : 2, then the A : B : C is -

If the angles of a triangle are in ratio 4 : 1: 1 then the ratio of the longest side and perimeter of triangle is -

If the angles of a triangle are in ratio 4 : 1: 1 then the ratio of the longest side and perimeter of triangle is -

Which of the following pieces of data does NOT uniquely determine an acute angled triangle ABC (R being the radius of the circumcircle) -

Which of the following pieces of data does NOT uniquely determine an acute angled triangle ABC (R being the radius of the circumcircle) -

parallel

In a triangle ABC, let C = $fraction numerator pi over denominator 2 end fraction$ . If r is the in radius and R is the circumradius of the triangle, then 2(r + R) is equal to -

In a triangle ABC, let C = $fraction numerator pi over denominator 2 end fraction$ . If r is the in radius and R is the circumradius of the triangle, then 2(r + R) is equal to -

The solution set of the equation $fraction numerator 1 over denominator left parenthesis x plus 3 right parenthesis end fraction less or equal than negative 2 space i s$

The solution set of the equation $fraction numerator 1 over denominator left parenthesis x plus 3 right parenthesis end fraction less or equal than negative 2 space i s$

Solution of $left parenthesis 5 x minus 1 right parenthesis less than left parenthesis x plus 1 right parenthesis squared less than left parenthesis 7 x minus 3 right parenthesis$ is

Solution of $left parenthesis 5 x minus 1 right parenthesis less than left parenthesis x plus 1 right parenthesis squared less than left parenthesis 7 x minus 3 right parenthesis$ is

parallel

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