The product (A) is:

If then  is always

  The compound (A) is:

The oxidation number of C in  is:

 has

In this question, we have to find the number of solution. In each quadrant tan value is different. Make two different case, one is where tan is positive ,[ 0 , π/2  ] U [π , 3 π/2 ] . And second case , tan is negative at [π/2 , π] U [3 π/2 , 2 π ] .

If then for all real values of q

 The products (A) , (B) and (C) are:

In the interval , the equation,  has

 oxidised product of , in the above reaction cannot be

Let a, b, c, d  R. Then the cubic equation of the type  has either one root real or all three roots are real. But in case of trigonometric equations of the type  can possess several solutions depending upon the domain of x. To solve an equation of the type a . The equation can be written as  The solution is  where  = 

On the domain [–, ] the equation  possess

 The products (A) and (B) are:

If w is a complex cube root of unity, then the matrix A =  is a-

Matrix [1 2] is equal to-

If A –2B = and 2A – 3B = , then matrix B is equal to–

The value of x for which the matrix A = is inverse of B = is