Chemistry-
General
Easy

Question

The size of the colloidal particles is in between

  1. 10 to the power of negative 7 end exponent minus 10 to the power of negative 9 end exponent cm
  2. 10 to the power of negative 9 end exponent minus 10 to the power of negative 11 end exponent cm
  3. 10 to the power of negative 5 end exponent minus 10 to the power of negative 7 end exponent cm
  4. 10 to the power of negative 2 end exponent minus 10 to the power of negative 3 end exponent cm

The correct answer is: 10 to the power of negative 5 end exponent minus 10 to the power of negative 7 end exponent cm

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The volumes of gases H2, CH4, CO2 and NH3 adsorbed by 1 g of charcoal at 288 K are in the order

The volumes of gases H2, CH4, CO2 and NH3 adsorbed by 1 g of charcoal at 288 K are in the order

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Consider the following equations for a cell reaction

straight A plus straight B not stretchy rightwards harpoon over leftwards harpoon straight C plus DE equals straight x volt , straight K subscript eq equals straight K subscript 1

2 straight A plus 2 straight B not stretchy rightwards harpoon over leftwards harpoon 2 straight C plus 2 DE to the power of ring operator equals straight y volt, straight K subscript eq equals straight K subscript 2

then :

Consider the following equations for a cell reaction

straight A plus straight B not stretchy rightwards harpoon over leftwards harpoon straight C plus DE equals straight x volt , straight K subscript eq equals straight K subscript 1

2 straight A plus 2 straight B not stretchy rightwards harpoon over leftwards harpoon 2 straight C plus 2 DE to the power of ring operator equals straight y volt, straight K subscript eq equals straight K subscript 2

then :

Chemistry-General
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From the following E to the power of ring operator values of half cells,

i) straight A to the power of 3 minus end exponent not stretchy ⟶ straight A to the power of negative 2 end exponent plus straight e semicolon straight E to the power of ring operator equals 1.5 straight V

ii) straight B to the power of plus plus straight e not stretchy ⟶ straight B semicolon straight E to the power of ring operator equals 0.5 straight V

iii) straight C to the power of 2 plus end exponent plus straight e not stretchy rightwards arrow straight C to the power of plus semicolon straight E to the power of ring operator equals 0.5 straight V

iv) straight D not stretchy rightwards arrow straight D to the power of 2 plus end exponent plus 2 straight e semicolon straight E to the power of ring operator equals negative 1.15 straight V

What combination of two half cells would result in a cell with the largest potential ?

From the following E to the power of ring operator values of half cells,

i) straight A to the power of 3 minus end exponent not stretchy ⟶ straight A to the power of negative 2 end exponent plus straight e semicolon straight E to the power of ring operator equals 1.5 straight V

ii) straight B to the power of plus plus straight e not stretchy ⟶ straight B semicolon straight E to the power of ring operator equals 0.5 straight V

iii) straight C to the power of 2 plus end exponent plus straight e not stretchy rightwards arrow straight C to the power of plus semicolon straight E to the power of ring operator equals 0.5 straight V

iv) straight D not stretchy rightwards arrow straight D to the power of 2 plus end exponent plus 2 straight e semicolon straight E to the power of ring operator equals negative 1.15 straight V

What combination of two half cells would result in a cell with the largest potential ?

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The emf of the cell in which the following reaction Zn invisible function application left parenthesis straight s right parenthesis plus Ni to the power of 2 plus end exponent left parenthesis straight a equals 0.1 right parenthesis Zn to the power of 2 plus end exponent left parenthesis straight a equals 1.0 right parenthesis plus Ni left parenthesis straight s right parenthesis occurs, is found to be 0.5105 V at 298 K. The standard e.m.f. of the cell is :

The emf of the cell in which the following reaction Zn invisible function application left parenthesis straight s right parenthesis plus Ni to the power of 2 plus end exponent left parenthesis straight a equals 0.1 right parenthesis Zn to the power of 2 plus end exponent left parenthesis straight a equals 1.0 right parenthesis plus Ni left parenthesis straight s right parenthesis occurs, is found to be 0.5105 V at 298 K. The standard e.m.f. of the cell is :

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Write the equation of the line.

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If 180 to the power of ring operator less than theta less than 270 to the power of 0 comma s i n space theta equals negative 3 divided by 5 then cos space theta divided by 2 equals

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x equals square root of fraction numerator 1 minus cos space theta over denominator 1 plus cos space theta end fraction end root not stretchy rightwards double arrow fraction numerator 2 x over denominator 1 minus x squared end fraction equals

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cos space theta equals 1 half open parentheses a plus 1 over a close parentheses text  then  end text cos text end text 3 theta equals K open parentheses a cubed plus 1 over a cubed close parentheses where  is equal to

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4 s i n cubed space 75 to the power of ring operator minus 3 c o s space 15 to the power of ring operator equals

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fraction numerator cos space A minus cos space 3 A over denominator cos space A end fraction plus fraction numerator sin begin display style space end style A plus sin space 3 A over denominator sin begin display style space end style A end fraction equals

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which of the following is rational number

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