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Maths-

General

Easy

Question

The value of $sin open parentheses a over 2 close parentheses open curly brackets 1 half plus sum from k equals 1 to n of cos left parenthesis k a right parenthesis close curly brackets$ is equal to

$\frac{1}{2} \sin ((n + \frac{1}{2}) a)$
$\frac{1}{2} \sin ((n - \frac{1}{2}) a)$
sin(n+1)a)
cos(n+1)a)

The correct answer is: $1 half sin open parentheses open parentheses n plus 1 half close parentheses a close parentheses$

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