To solve a trigonometric inequation of the type sin x ≥ a where |a| ≤ 1, we take a hill of length 2  in the sine curve and write the solution within that hill. For the general solution, we add 2n. For instance, to solve , we take the hill  over which solution is  The general solution is , n is any integer. Again to solve an inequation of the type sin x ≤ a, where |a| ≤ 1, we take a hollow of length 2 in the sine curve. (since on a hill, sinx ≤ a is satisfied over two intervals). Similarly cos x ≥ a or cosx ≤a, |a| ≤ 1 are solved.

Solution to the inequation  must be

Which of the following compounds does not give halo form reaction?

The oxidation number of carboxylic carbon atom in  is:

The oxidation number of carboxylic carbon atom in  is:

 The product (A) is:

If then  is always

  The compound (A) is:

The oxidation number of C in  is:

 has

In this question, we have to find the number of solution. In each quadrant tan value is different. Make two different case, one is where tan is positive ,[ 0 , π/2  ] U [π , 3 π/2 ] . And second case , tan is negative at [π/2 , π] U [3 π/2 , 2 π ] .

If then for all real values of q

 The products (A) , (B) and (C) are:

In the interval , the equation,  has

 oxidised product of , in the above reaction cannot be

Let a, b, c, d  R. Then the cubic equation of the type  has either one root real or all three roots are real. But in case of trigonometric equations of the type  can possess several solutions depending upon the domain of x. To solve an equation of the type a . The equation can be written as  The solution is  where  = 

On the domain [–, ] the equation  possess

 The products (A) and (B) are: