Maths-
General
Easy
Question
Two poles 30m and 15 m high stand upright in a ground. If their feet are 36m apart, find the distance between their tops?
Hint:
Pythagoras' theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.
If a is the perpendicular, b is the base, and c is the hypotenuse, then according to the definition, the Pythagoras Theorem formula is given as
c2= a2 + b2
The correct answer is: Hence, the distance between the top of the poles is 39 m.
Two poles are given AB = 30 m and CD = 15 m
Distance between both poles BC = 36 m
First, create a line segment DE parallel to line BC
So, BE = CD = 15 m and ED = BC = 36 m
Now, AE = AB − BE =30 − 15 = 15 m
In right angled △AED,
(AD)2 = (AE)2 + (ED)2
(AC)2 = (15)2 + (36)2
(AC)2 = 1521
AC = 39 m
Final Answer:
(AD)2 = (AE)2 + (ED)2
(AC)2 = (15)2 + (36)2
(AC)2 = 1521
AC = 39 m
Final Answer:
(AD)2 = (AE)2 + (ED)2
(AC)2 = (15)2 + (36)2
(AC)2 = 1521
AC = 39 m
Final Answer:
Hence, the distance between the top of the poles is 39 m.
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