Maths-
General
Easy

Question

What is the perpendicular distance between two parallel lines 4x + 3y = 6 and 8x+ 6y = - 3?

hintHint:

Distance d between two parallel lines y = mx + c1 and y = mx + c2 is given by

d = fraction numerator open vertical bar C subscript 1 minus C subscript 2 close vertical bar over denominator square root of 1 plus m squared end root end fraction

The correct answer is: 1.5 units


    y = mx + c form of 4x + 3y = 6 is y = negative 4 over 3 x + 2
    y = mx + c form of 8x + 6y = -3 is y = negative 4 over 3 x – negative 1 half
    So, C1 = 2, C2negative 1 half and m = - 4 over 3
    Using formula, d = fraction numerator open vertical bar C subscript 1 minus C subscript 2 close vertical bar over denominator square root of 1 plus m squared end root end fraction

    equals fraction numerator open vertical bar 2 minus open parentheses negative 1 half close parentheses close vertical bar over denominator square root of 1 plus open parentheses negative 4 over 3 close parentheses squared end root end fraction

    equals fraction numerator 5 over 2 over denominator square root of 1 plus 16 over 9 end root end fraction

    equals fraction numerator 5 over 2 over denominator square root of 25 over 9 end root end fraction equals fraction numerator 2 over 5 over denominator 3 over 3 end fraction equals 3 over 2 equals 1.5 units
    Final Answer:
    Hence, the distance between parallel lines 4x + 3y = 6 and 8x + 6y = - 3 is 1.5 units

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