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Which of the following is not a disporportionation reaction?

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If f(alpha) = open square brackets table row cell cos invisible function application alpha end cell cell negative sin invisible function application alpha end cell 0 row cell sin invisible function application alpha end cell cell cos invisible function application alpha end cell 0 row 0 0 1 end table close square brackets, then open square brackets f left parenthesis alpha right parenthesis close square brackets to the power of negative 1 end exponent =

If f(alpha) = open square brackets table row cell cos invisible function application alpha end cell cell negative sin invisible function application alpha end cell 0 row cell sin invisible function application alpha end cell cell cos invisible function application alpha end cell 0 row 0 0 1 end table close square brackets, then open square brackets f left parenthesis alpha right parenthesis close square brackets to the power of negative 1 end exponent =

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If A = open square brackets table row 0 1 2 row 1 2 3 row 3 a 1 end table close square brackets and A–1 = open square brackets table row cell 1 divided by 2 end cell cell negative 1 divided by 2 end cell cell 1 divided by 2 end cell row cell negative 4 end cell 3 c row cell 5 divided by 2 end cell cell negative 3 divided by 2 end cell cell 1 divided by 2 end cell end table close square brackets then value of a and c is -

If A = open square brackets table row 0 1 2 row 1 2 3 row 3 a 1 end table close square brackets and A–1 = open square brackets table row cell 1 divided by 2 end cell cell negative 1 divided by 2 end cell cell 1 divided by 2 end cell row cell negative 4 end cell 3 c row cell 5 divided by 2 end cell cell negative 3 divided by 2 end cell cell 1 divided by 2 end cell end table close square brackets then value of a and c is -

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A skew symmetric matrix S satisfies the relation S2 + I = 0, where I is a unit matrix, then SS´ is -

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If the matrix open square brackets table row 0 cell 2 beta end cell gamma row alpha beta cell negative gamma end cell row alpha cell negative beta end cell gamma end table close square brackets is orthogonal, then

If the matrix open square brackets table row 0 cell 2 beta end cell gamma row alpha beta cell negative gamma end cell row alpha cell negative beta end cell gamma end table close square brackets is orthogonal, then

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If A equals open square brackets table row cell cos to the power of 2 end exponent invisible function application theta end cell cell cos invisible function application theta sin invisible function application theta end cell row cell cos invisible function application theta sin invisible function application theta end cell cell sin to the power of 2 end exponent invisible function application theta end cell end table close square brackets andB equals open square brackets table row cell cos to the power of 2 end exponent invisible function application phi end cell cell cos invisible function application phi sin invisible function application phi end cell row cell cos invisible function application phi sin invisible function application phi end cell cell sin to the power of 2 end exponent invisible function application phi end cell end table close square brackets are two matrices such that the product AB is the null matrix then theta minus ϕ is equal to

If A equals open square brackets table row cell cos to the power of 2 end exponent invisible function application theta end cell cell cos invisible function application theta sin invisible function application theta end cell row cell cos invisible function application theta sin invisible function application theta end cell cell sin to the power of 2 end exponent invisible function application theta end cell end table close square brackets andB equals open square brackets table row cell cos to the power of 2 end exponent invisible function application phi end cell cell cos invisible function application phi sin invisible function application phi end cell row cell cos invisible function application phi sin invisible function application phi end cell cell sin to the power of 2 end exponent invisible function application phi end cell end table close square brackets are two matrices such that the product AB is the null matrix then theta minus ϕ is equal to

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If the lines of regression are 3x+12y=19 and 3y+9x=46 then r subscript x y end subscriptwill be

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If regression coefficient of y on x is fraction numerator 8 over denominator 5 end fraction and that of x on y is fraction numerator 2 over denominator 5 end fractionand the acute angle between the two lines is alpha, then the value of tan invisible function application alpha is

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The coefficient of correlation for the following data will be

The coefficient of correlation for the following data will be

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For the following data

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The coefficient of correlation for the following will be approximately

The coefficient of correlation for the following will be approximately

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If correlation between x and y is r, then between y and x correlation will be

If correlation between x and y is r, then between y and x correlation will be

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If r=-0.97, then

If r=-0.97, then

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If r=0.2, then linear correlation will be necessarily

If r=0.2, then linear correlation will be necessarily

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Coefficient of correlation between x and y for the following data will be approximately

Coefficient of correlation between x and y for the following data will be approximately

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Coefficient of correlation from the following data will be

Coefficient of correlation from the following data will be

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