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Chemistry-

General

Easy

Question

Which of the following represents Westrosol?

${CHCl}_{3}$
${CH}_{2} {Cl}_{2}$
${CHCl}_{2} {CH}_{2} Cl$
${CCl}_{2} = CHCl$

The correct answer is: $CCl subscript 2 equals CHCl$

Related Questions to study

Which of the following sequences would yield -nitro chlorobenzene (Z) from benzene?

Which of the following sequences would yield -nitro chlorobenzene (Z) from benzene?

Chemistry-General

For the preparation of chloroethane

For the preparation of chloroethane

Chemistry-General

Which of the following statements is wrong about the reaction?

Which of the following statements is wrong about the reaction?

Chemistry-General

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In the following reaction, the final product can be prepared by two paths (I) and (II).
Which of the following statements is correct?

In the following reaction, the final product can be prepared by two paths (I) and (II).
Which of the following statements is correct?

Chemistry-General

The final product (X) in the following reaction is:

The final product (X) in the following reaction is:

Chemistry-General

Ethylmercaptan is prepared by the reaction of the following, followed by hydrolysis

Ethylmercaptan is prepared by the reaction of the following, followed by hydrolysis

Chemistry-General

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Two adjacent sides of a parallelogram $A B C D$ are given by $stack A B with minus on top equals 2 i with ‾ on top plus 10 j with ‾ on top plus 11 k with ‾ on top$ and $stack A D with minus on top equals negative i with ‾ on top plus 2 j with ‾ on top plus 2 k with ‾ on top$ . The side $A D$ is rotated by an acute angle $alpha$ in the plane of parallelogram so that $A D$ becomes AD’. If $A D$ makes a right angle with the side AB then the cosine of angle $alpha$ is given by

Two adjacent sides of a parallelogram $A B C D$ are given by $stack A B with minus on top equals 2 i with ‾ on top plus 10 j with ‾ on top plus 11 k with ‾ on top$ and $stack A D with minus on top equals negative i with ‾ on top plus 2 j with ‾ on top plus 2 k with ‾ on top$ . The side $A D$ is rotated by an acute angle $alpha$ in the plane of parallelogram so that $A D$ becomes AD’. If $A D$ makes a right angle with the side AB then the cosine of angle $alpha$ is given by

If $a with ‾ on top equals 2 i with ‾ on top plus 3 j with ‾ on top plus k with ‾ on top comma a with ‾ on top cross times b with ‾ on top equals 7 i with ‾ on top minus 3 j with ‾ on top minus 5 k with ‾ on top comma a with ‾ on top times b with ‾ on top equals 1$ then $stack b with ‾ on top equals$

If $a with ‾ on top equals 2 i with ‾ on top plus 3 j with ‾ on top plus k with ‾ on top comma a with ‾ on top cross times b with ‾ on top equals 7 i with ‾ on top minus 3 j with ‾ on top minus 5 k with ‾ on top comma a with ‾ on top times b with ‾ on top equals 1$ then $stack b with ‾ on top equals$

If $Error converting from MathML to accessible text.$ are non coplanar vectors then the roots of equation $open square brackets table attributes columnalign left left left columnspacing 1em end attributes row cell left square bracket b with not stretchy bar on top cross times c with not stretchy bar on top c with not stretchy bar on top cross times a with not stretchy bar on top a with not stretchy bar on top cross times b with not stretchy bar on top end cell end table close square brackets x squared$ $Error converting from MathML to accessible text.$ $plus left square bracket b with not stretchy bar on top minus c with not stretchy bar on top c with not stretchy bar on top minus a with not stretchy bar on top a with not stretchy bar on top minus b with not stretchy bar on top right square bracket plus 1 equals 0$

If $Error converting from MathML to accessible text.$ are non coplanar vectors then the roots of equation $open square brackets table attributes columnalign left left left columnspacing 1em end attributes row cell left square bracket b with not stretchy bar on top cross times c with not stretchy bar on top c with not stretchy bar on top cross times a with not stretchy bar on top a with not stretchy bar on top cross times b with not stretchy bar on top end cell end table close square brackets x squared$ $Error converting from MathML to accessible text.$ $plus left square bracket b with not stretchy bar on top minus c with not stretchy bar on top c with not stretchy bar on top minus a with not stretchy bar on top a with not stretchy bar on top minus b with not stretchy bar on top right square bracket plus 1 equals 0$

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If the squares of the lengths of the tangents from a point P to the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent$ , $x to the power of 2 end exponent plus y to the power of 2 end exponent equals b to the power of 2 end exponent$ and $x to the power of 2 end exponent plus y to the power of 2 end exponent equals c to the power of 2 end exponent$ are in A.P then $a to the power of 2 end exponent comma b to the power of 2 end exponent comma c to the power of 2 end exponent$ are in

If the squares of the lengths of the tangents from a point P to the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent equals a to the power of 2 end exponent$ , $x to the power of 2 end exponent plus y to the power of 2 end exponent equals b to the power of 2 end exponent$ and $x to the power of 2 end exponent plus y to the power of 2 end exponent equals c to the power of 2 end exponent$ are in A.P then $a to the power of 2 end exponent comma b to the power of 2 end exponent comma c to the power of 2 end exponent$ are in

In the following redox reaction, $Cu left parenthesis OH right parenthesis subscript 2 left parenthesis straight s right parenthesis plus straight N subscript 2 straight H subscript 4 left parenthesis aq right parenthesis not stretchy rightwards arrow Cu left parenthesis straight s right parenthesis plus straight N subscript 2 left parenthesis straight g right parenthesis$ Number of moles of $Cu left parenthesis OH right parenthesis subscript 2$ reduced by 1 mole of $straight N subscript 2 straight H subscript 4$ is

In the following redox reaction, $Cu left parenthesis OH right parenthesis subscript 2 left parenthesis straight s right parenthesis plus straight N subscript 2 straight H subscript 4 left parenthesis aq right parenthesis not stretchy rightwards arrow Cu left parenthesis straight s right parenthesis plus straight N subscript 2 left parenthesis straight g right parenthesis$ Number of moles of $Cu left parenthesis OH right parenthesis subscript 2$ reduced by 1 mole of $straight N subscript 2 straight H subscript 4$ is

Chemistry-General

The vector $i with minus on top cross times left square bracket left parenthesis a with ‾ on top cross times b with ‾ on top right parenthesis cross times i with ‾ on top right parenthesis right square bracket plus j with ‾ on top cross times left square bracket left parenthesis a with ‾ on top cross times b with ‾ on top right parenthesis cross times j with ‾ on top right square bracket plus k with ‾ on top cross times left square bracket left parenthesis a with ‾ on top cross times b with ‾ on top right parenthesis cross times k with ‾ on top right square bracket$ equals

The vector $i with minus on top cross times left square bracket left parenthesis a with ‾ on top cross times b with ‾ on top right parenthesis cross times i with ‾ on top right parenthesis right square bracket plus j with ‾ on top cross times left square bracket left parenthesis a with ‾ on top cross times b with ‾ on top right parenthesis cross times j with ‾ on top right square bracket plus k with ‾ on top cross times left square bracket left parenthesis a with ‾ on top cross times b with ‾ on top right parenthesis cross times k with ‾ on top right square bracket$ equals

parallel

Let $a with ‾ on top equals i with ˆ on top plus j with ˆ on top plus k with rightwards arrow on top times b with rightwards arrow on top equals left square bracket x right square bracket i with ˆ on top plus left curly bracket s i n invisible function application left parenthesis x right parenthesis right curly bracket j comma c equals c subscript 1 i with ˆ on top plus c subscript 2 j with ˆ on top plus c subscript 3 k with ˆ on top$ be three non zero vectors,
such that $vertical line stack c with rightwards arrow on top vertical line equals 1$ angle between $stack a with ‾ on top$ and $stack b with ‾ on top$ is $fraction numerator pi over denominator 4 end fraction$ , $stack c with rightwards arrow on top$ is perpendicular to both $stack a with rightwards arrow on top$ and $stack b with ‾ on top$ . (where $left square bracket x right square bracket equals$ Greatest integer function and $left curly bracket x right curly bracket equals$ Fractional part of $x right parenthesis$ . If $f left parenthesis x right parenthesis equals left parenthesis stack a with rightwards arrow on top left parenthesis stack b with ‾ on top cross times stack c with ‾ on top right parenthesis right parenthesis to the power of 2 end exponent$ , then which of the following is correct for $f left parenthesis x right parenthesis$

Let $a with ‾ on top equals i with ˆ on top plus j with ˆ on top plus k with rightwards arrow on top times b with rightwards arrow on top equals left square bracket x right square bracket i with ˆ on top plus left curly bracket s i n invisible function application left parenthesis x right parenthesis right curly bracket j comma c equals c subscript 1 i with ˆ on top plus c subscript 2 j with ˆ on top plus c subscript 3 k with ˆ on top$ be three non zero vectors,
such that $vertical line stack c with rightwards arrow on top vertical line equals 1$ angle between $stack a with ‾ on top$ and $stack b with ‾ on top$ is $fraction numerator pi over denominator 4 end fraction$ , $stack c with rightwards arrow on top$ is perpendicular to both $stack a with rightwards arrow on top$ and $stack b with ‾ on top$ . (where $left square bracket x right square bracket equals$ Greatest integer function and $left curly bracket x right curly bracket equals$ Fractional part of $x right parenthesis$ . If $f left parenthesis x right parenthesis equals left parenthesis stack a with rightwards arrow on top left parenthesis stack b with ‾ on top cross times stack c with ‾ on top right parenthesis right parenthesis to the power of 2 end exponent$ , then which of the following is correct for $f left parenthesis x right parenthesis$

If $a subscript 1 end subscript$ and $a subscript 2 end subscript$ are two values of a for which the unit vector $a i with minus on top plus b j with minus on top plus 1 half k with minus on top$ is linearly dependent with $i with minus on top plus 2 j$ and $stack j with minus on top minus 2 stack k with minus on top$ then $fraction numerator 1 over denominator a subscript 1 end subscript end fraction plus fraction numerator 1 over denominator a subscript 2 end subscript end fraction$ is equal to

If $a subscript 1 end subscript$ and $a subscript 2 end subscript$ are two values of a for which the unit vector $a i with minus on top plus b j with minus on top plus 1 half k with minus on top$ is linearly dependent with $i with minus on top plus 2 j$ and $stack j with minus on top minus 2 stack k with minus on top$ then $fraction numerator 1 over denominator a subscript 1 end subscript end fraction plus fraction numerator 1 over denominator a subscript 2 end subscript end fraction$ is equal to

$stack a with rightwards arrow on top subscript i end subscript comma i element of left curly bracket 1 , 2 comma 3 right curly bracket$ are three vectors such that $open vertical bar stack a subscript i end subscript with rightwards arrow on top close vertical bar equals square root of 15$ and $open vertical bar a with rightwards arrow on top subscript i minus a with rightwards arrow on top subscript j close vertical bar equals 6$ for $i not equal to j$ . Then the value of $open square brackets stack a subscript 1 end subscript with rightwards arrow on top stack blank a subscript 2 blank end subscript with rightwards arrow on top stack a subscript 3 end subscript with rightwards arrow on top close square brackets$ is equal to

$stack a with rightwards arrow on top subscript i end subscript comma i element of left curly bracket 1 , 2 comma 3 right curly bracket$ are three vectors such that $open vertical bar stack a subscript i end subscript with rightwards arrow on top close vertical bar equals square root of 15$ and $open vertical bar a with rightwards arrow on top subscript i minus a with rightwards arrow on top subscript j close vertical bar equals 6$ for $i not equal to j$ . Then the value of $open square brackets stack a subscript 1 end subscript with rightwards arrow on top stack blank a subscript 2 blank end subscript with rightwards arrow on top stack a subscript 3 end subscript with rightwards arrow on top close square brackets$ is equal to

parallel

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