10th-Grade-Math---USA

Piecewise-Functions

Easy

Question

The value of f(2) + f(4) + f(11) + f(12) for the function
$f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell 100 comma end cell cell 0 less than x less or equal than 4 end cell row cell 95 comma end cell cell 4 less than x less or equal than 8 end cell row cell 90 comma end cell cell 8 less than x less or equal than 12 end cell row cell 95 comma end cell cell 12 less than x less or equal than 16 end cell end table close$ is

29
280
290
380

The correct answer is: 380

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

let $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell x minus 1 comma end cell cell x less than 4 end cell row cell negative x plus 4 comma end cell cell x greater or equal than 4 end cell end table close$ , the range of f is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

Let $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell x minus 1 comma end cell cell x less than 4 end cell row cell negative x plus 4 comma end cell cell x greater or equal than 4 end cell end table close$ then the value of f(4) is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

Let f(x) = |x|. The point that do not lie on the graph of the function is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

|-5.987| =

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

The range of f(x) = |x| + 4 is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

From the graph identify the function.

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

$left floor 5.98 right floor plus open ceil 5.0001 close ceil$ =

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

$left floor 2.78 right floor$ =

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

$left ceiling 2.78 right ceiling$ =

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

Function having the same graph as f(x) = 0.1|x| is

10th-Grade-Math---USAPiecewise-Functions

Piecewise-Functions

10th-Grade-Math---USA

Let $f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell negative 3 x plus 1 comma end cell cell x less or equal than 1 end cell row cell x plus 1 comma end cell cell x greater than 1 end cell end table close$ then the range of f is

10th-Grade-Math---USAPiecewise-Functions

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The value of f(2) + f(4) + f(11) + f(12) for the functionis

29280290380

The correct answer is: 380

Related Questions to study

=

=

The function from the graph is

The function from the graph is

=

=

=

=

let , the range of f is

let , the range of f is

Let then the value of f(4) is

Let then the value of f(4) is

Let f(x) = |x|. The point that do not lie on the graph of the function is

Let f(x) = |x|. The point that do not lie on the graph of the function is

|-5.987| =

|-5.987| =

The range of f(x) = |x| + 4 is

The range of f(x) = |x| + 4 is

From the graph identify the function.

From the graph identify the function.

=

=

=

=

=

=

Function having the same graph as f(x) = 0.1|x| is

Function having the same graph as f(x) = 0.1|x| is

Let then the range of f is

Let then the range of f is

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29
280
290
380

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =

$left floor negative 2.54 right floor$ =

$left floor negative 2.54 right floor$ =

$left ceiling negative 2.54 right ceiling$ =

$left ceiling negative 2.54 right ceiling$ =

$left floor 5.98 right floor plus open ceil 5.0001 close ceil$ =

$left floor 5.98 right floor plus open ceil 5.0001 close ceil$ =

$left floor 2.78 right floor$ =

$left floor 2.78 right floor$ =

$left ceiling 2.78 right ceiling$ =

$left ceiling 2.78 right ceiling$ =