Maths-
General
Easy
Question
16 sin 
- [-1,1]
- [
] - [
] - [
]
]]]
Hint:
In this question, we have to find the range of 8 sin x.cos x.cos 2x.cos 4x.cos 8x. For that first we will simplify the trigonometric function and later as we know range of sin y and cos y is [-1,1], so, using this we can find the range of the given function.
The correct answer is: [-1,1]
f(x) = 8 sin x.co x.cos 2x.cos 4x.cos 8x
=4sin 2x.cos 4x.cos 8x
=2sin 8x.cos 8x
=sin 16x
So, range is [-1, 1].
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