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9th-Grade-Math---USA

Similarity

Easy

Question

If triangles ABC and DEF are similar, then the statement that is not correct is

$\frac{B C}{E F} = \frac{B C}{E F}$
$\frac{A B}{D E} = \frac{C A}{F D}$
$\frac{C A}{F D} = \frac{B C}{E F}$
$\frac{A B}{E F} = \frac{B C}{D E}$

The correct answer is: $fraction numerator A B over denominator E F end fraction equals fraction numerator B C over denominator D E end fraction$

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