Chemistry-
General
Easy
Question
20 mL of KOH solution was titrated with 0.20 M 
solution in a conductivity cell. The data obtained were plotted to give the graph shown below
The concentration of the KOH solution was
- 0.30 mol
- 0.15 mol
- 0.12 mol
- 0.075 mol
The correct answer is: 0.30 mol
Equivalent point 
(from graph)
Using 
of acid 
of base
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First form of the complex is
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