Chemistry
Grade-9
Easy
Question
A compound of Al and Cl is composed of 9gm of Al for every 35.5g of Cl. What is the empirical formula?
- Al2Cl
- AlCl
- AlCl3
- Al3Cl
Hint:
Oxidation state of aluminum is +3 and that of chlorine is -1.
The correct answer is: AlCl3
Atomic mass of aluminum is 27g and that of chlorine is 35.5g.
A compound of Al and Cl is composed of 9g of Al for every 35.5g of Cl. From this information we can say that for 1/3 moles of aluminum 1mole of chlorine is present. Also we know oxidation state of aluminum is +3 and that of chlorine is -1. For a neutral compound one aluminum requires three chlorine atoms. Hence, the empirical formula is AlCl3.
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