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    Chemistry-
    General
    Easy

    Question

    A drop of solution (volume 0.05 ml) contains 3 cross times 10–6 moles of H+. If the rate constant of disappearance of H+ is 1 cross times 107 mole litre–1 sec–1. How long would it take for H+ in drop to disappear.

    1. 6 cross times 10–8 sec    
    2. 6 cross times 10–7 sec    
    3. 6 cross times 10–9 sec    
    4. 6 cross times 10–10 sec    

    The correct answer is: 6 cross times 10–9 sec

      Since rate constant = 1.0 ´ 107 mol litre–1 sec
      \ Zero order reaction
      For zero order reaction t = fraction numerator x over denominator K end fraction equals fraction numerator C o n c e n t r a t i o n u s e d over denominator r a t e c o n s tan invisible function application t end fraction…(I)
      Q 0.05 mL has 3 ´ 10–6 moles of H+
      \ 1000 mL has fraction numerator 3 cross times 1 0 to the power of negative 6 end exponent cross times 1 0 to the power of 3 end exponent over denominator 0.05 end fraction = 0.6 ´ 10–1 mol/litre
      \ By equation (1) t = fraction numerator 0.6 cross times 1 0 to the power of negative 1 end exponent over denominator 1 cross times 1 0 to the power of 7 end exponent end fraction = 6 ´ 10–9 sec

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