Chemistry-
General
Easy
Question
An organic compound ‘A’ has the molecular formula C3H6O. It undergoes iodoform test. When saturated with HCl it gives ‘B’ of molecular formula C9H14O, ‘A’ & ‘B’ respectively are
- propanal & mesitylene
- propanone & mesityl oxide
- propanone & 2, 6 – dimethyl – 2, 5 – heptadien – 4 – one
- propane & meistylene oxide
The correct answer is: propanone & 2, 6 – dimethyl – 2, 5 – heptadien – 4 – one
Since the compound A has the molecular formula C3H6O & undergoes iodoform test, it should be CH3COCH3. Further reaction of B with HCl gives C9H14O, this should be trimer of acetone, i.e. It should be phorone.
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