Chemistry
Grade-10
Easy
Question
Aqueous solution of ‘X’ on treatment with copper sulphate solution gives a blue precipitate of ‘Y’. What could be X and Y??
- X is NH3; Y → Cu (OH)2
- X is NaOH; Y → Cu (OH)
- X is NH3; Y → Cu (OH)2
- X is NaOH; Y → Cu (OH)2
Hint:
Sodium sulphate is a by-product.
The correct answer is: X is NaOH; Y → Cu (OH)2
-
When sodium hydroxide, a strong base, reacts with copper sulphate, an acidic salt, a blue precipitate of copper hydroxide is produced with the ions of sodium sulphate in solution. It is a double displacement reaction, as well as a precipitation reaction.
- The reaction is as: NaOH + CuSO4
Cu(OH)2 + Na2SO4.
- X and Y are sodium hydroxide and copper hydroxide respectively.
When sodium hydroxide, a strong base, reacts with copper sulphate, an acidic salt, a blue precipitate of copper hydroxide is produced with the ions of sodium sulphate in solution. It is a double displacement reaction, as well as a precipitation reaction.
Cu(OH)2 + Na2SO4.Related Questions to study
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