Chemistry-
General
Easy

Question

Consider the following halogen-containing compounds;
I) C H C l subscript 3 end subscript
II) C C l subscript 4 end subscript
III) C H subscript 2 end subscript C l subscript 2 end subscript
IV) C H subscript 3 end subscript C l
V)

  1. (II),(V)    
  2. (II)    
  3. (III),(IV)    
  4. (I),(IV)    

The correct answer is: (II),(V)


    In (II) and (IV), the dipole vectors are cancelled, so there is zero dipole moment

    Related Questions to study

    General
    Chemistry-

    Which of the following mentioned positions in the given compound is more reactive towards electrophilic substitutions?

    Which of the following mentioned positions in the given compound is more reactive towards electrophilic substitutions?

    Chemistry-General
    General
    Maths-

    Two adjacent sides of a parallelogram ABCD are given by stack A B with minus on top equals 2 i with minus on top plus 10 j with rightwards arrow on top plus 11 k with minus on top and stack A D with rightwards arrow on top equals negative i with minus on top plus 2 j with minus on top plus 2 k with minus on top. The side AD is rotated by an acute angle alpha in the plane of parallelogram so that AD becomes AD. If AD makes a right angle with the side AB then the cosine of angle alpha is given by

    Two adjacent sides of a parallelogram ABCD are given by stack A B with minus on top equals 2 i with minus on top plus 10 j with rightwards arrow on top plus 11 k with minus on top and stack A D with rightwards arrow on top equals negative i with minus on top plus 2 j with minus on top plus 2 k with minus on top. The side AD is rotated by an acute angle alpha in the plane of parallelogram so that AD becomes AD. If AD makes a right angle with the side AB then the cosine of angle alpha is given by

    Maths-General
    General
    Maths-

    At A, h>0 and alpha with ‾ on top equals fraction numerator i with ˆ on top over denominator a end fraction plus fraction numerator 4 j with ˆ on top over denominator b end fraction plus b k with ˆ on top 1192720 and beta with rightwards arrow on top equals b i with ˆ on top plus a j plus 1 over b k with ˆ on top, then the maximum value of fraction numerator 10 over denominator 5 plus stack alpha with rightwards arrow on top times beta end fraction is

    At A, h>0 and alpha with ‾ on top equals fraction numerator i with ˆ on top over denominator a end fraction plus fraction numerator 4 j with ˆ on top over denominator b end fraction plus b k with ˆ on top 1192720 and beta with rightwards arrow on top equals b i with ˆ on top plus a j plus 1 over b k with ˆ on top, then the maximum value of fraction numerator 10 over denominator 5 plus stack alpha with rightwards arrow on top times beta end fraction is

    Maths-General
    parallel
    General
    Maths-

    The position vector of a point P is r with rightwards arrow on top equals x i with ˆ on top plus y j plus z k with ˆ on top where x comma y comma z element of N and a with ‾ on top equals i with ˆ on top plus 2 j plus k with ˆ on top. If stack r with rightwards arrow on top blank stack a with rightwards arrow on top equals 20, the number of possible position of P is

    The position vector of a point P is r with rightwards arrow on top equals x i with ˆ on top plus y j plus z k with ˆ on top where x comma y comma z element of N and a with ‾ on top equals i with ˆ on top plus 2 j plus k with ˆ on top. If stack r with rightwards arrow on top blank stack a with rightwards arrow on top equals 20, the number of possible position of P is

    Maths-General
    General
    Maths-

    L t subscript left parenthesis x rightwards arrow infinity right parenthesis invisible function application left parenthesis 3 x cubed plus 4 x plus 5 right parenthesis divided by left parenthesis 2 x cubed plus 3 x minus 7 right parenthesis

    For such questions, we should know different formulas of limit.

    L t subscript left parenthesis x rightwards arrow infinity right parenthesis invisible function application left parenthesis 3 x cubed plus 4 x plus 5 right parenthesis divided by left parenthesis 2 x cubed plus 3 x minus 7 right parenthesis

    Maths-General

    For such questions, we should know different formulas of limit.

    General
    Maths-

    L t subscript left parenthesis x rightwards arrow 3 right parenthesis invisible function application left parenthesis 4 x squared minus 17 x plus 15 right parenthesis divided by left parenthesis x squared minus x minus 6 right parenthesis

    For such questions, we should know different formulas of limits. We should try different methods to simplify the function in a way that it doesn't become zero.

    L t subscript left parenthesis x rightwards arrow 3 right parenthesis invisible function application left parenthesis 4 x squared minus 17 x plus 15 right parenthesis divided by left parenthesis x squared minus x minus 6 right parenthesis

    Maths-General

    For such questions, we should know different formulas of limits. We should try different methods to simplify the function in a way that it doesn't become zero.

    parallel
    General
    Maths-

    L t left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis √ left parenthesis 1 plus x right parenthesis minus √ left parenthesis 1 plus x squared right parenthesis right parenthesis divided by left parenthesis √ left parenthesis 1 minus x squared right parenthesis minus √ left parenthesis 1 minus x right parenthesis right parenthesis

    L t left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis √ left parenthesis 1 plus x right parenthesis minus √ left parenthesis 1 plus x squared right parenthesis right parenthesis divided by left parenthesis √ left parenthesis 1 minus x squared right parenthesis minus √ left parenthesis 1 minus x right parenthesis right parenthesis

    Maths-General
    General
    Maths-

    L t left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis √ left parenthesis left parenthesis 1 plus x plus x squared right parenthesis right parenthesis minus 1 right parenthesis divided by x

    For such questions, we should know different formulas of limits.

    L t left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis √ left parenthesis left parenthesis 1 plus x plus x squared right parenthesis right parenthesis minus 1 right parenthesis divided by x

    Maths-General

    For such questions, we should know different formulas of limits.

    General
    Maths-

    L t subscript left parenthesis x rightwards arrow 3 right parenthesis invisible function application left parenthesis x cubed minus 8 x squared plus 45 right parenthesis divided by left parenthesis 2 x squared minus 3 x minus 9 right parenthesis

    L t subscript left parenthesis x rightwards arrow 3 right parenthesis invisible function application left parenthesis x cubed minus 8 x squared plus 45 right parenthesis divided by left parenthesis 2 x squared minus 3 x minus 9 right parenthesis

    Maths-General
    parallel
    General
    Maths-

    L t subscript left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis e to the power of t a n invisible function application x minus e to the power of x right parenthesis divided by left parenthesis t a n invisible function application x minus x right parenthesis

    For such questions, we should know different formulas of limits.

    L t subscript left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis e to the power of t a n invisible function application x minus e to the power of x right parenthesis divided by left parenthesis t a n invisible function application x minus x right parenthesis

    Maths-General

    For such questions, we should know different formulas of limits.

    General
    Maths-

    L t subscript left parenthesis x rightwards arrow 0 right parenthesis left parenthesis x times 2 to the power of x minus x right parenthesis divided by left parenthesis 1 minus c o s invisible function application x right parenthesis

    For such questions, we should know different formulas of limits.

    L t subscript left parenthesis x rightwards arrow 0 right parenthesis left parenthesis x times 2 to the power of x minus x right parenthesis divided by left parenthesis 1 minus c o s invisible function application x right parenthesis

    Maths-General

    For such questions, we should know different formulas of limits.

    General
    Maths-

    L t left parenthesis x rightwards arrow pi divided by 2 right parenthesis left parenthesis s e c invisible function application x minus t a n invisible function application x right parenthesis divided by left parenthesis pi divided by 2 minus x right parenthesis

    L t left parenthesis x rightwards arrow pi divided by 2 right parenthesis left parenthesis s e c invisible function application x minus t a n invisible function application x right parenthesis divided by left parenthesis pi divided by 2 minus x right parenthesis

    Maths-General
    parallel
    General
    Maths-

    L t subscript left parenthesis x rightwards arrow pi divided by 2 right parenthesis left square bracket s e c invisible function application 3 x c o s invisible function application 5 x right square bracket

    For such questions, we should know different formulas of limits. We should know L'Hospitals rule to solve question.

    L t subscript left parenthesis x rightwards arrow pi divided by 2 right parenthesis left square bracket s e c invisible function application 3 x c o s invisible function application 5 x right square bracket

    Maths-General

    For such questions, we should know different formulas of limits. We should know L'Hospitals rule to solve question.

    General
    Maths-

    L t left parenthesis x rightwards arrow pi divided by 2 right parenthesis left square bracket s e c 3 x c o s 5 x right square bracket

    L t left parenthesis x rightwards arrow pi divided by 2 right parenthesis left square bracket s e c 3 x c o s 5 x right square bracket

    Maths-General
    General
    Chemistry-

    K1 and K2 are equilibrium constants for reaction (i) and (ii)
    N subscript 2 end subscript left parenthesis g right parenthesis plus O subscript 2 end subscript left parenthesis g right parenthesis ℶ 2 N O left parenthesis g right parenthesis (i) N O left parenthesis g right parenthesis 1 divided by 2 N subscript 2 end subscript left parenthesis g right parenthesis plus 1 divided by 2 O subscript 2 end subscript left parenthesis g right parenthesis minus (ii) Then,

    K1 and K2 are equilibrium constants for reaction (i) and (ii)
    N subscript 2 end subscript left parenthesis g right parenthesis plus O subscript 2 end subscript left parenthesis g right parenthesis ℶ 2 N O left parenthesis g right parenthesis (i) N O left parenthesis g right parenthesis 1 divided by 2 N subscript 2 end subscript left parenthesis g right parenthesis plus 1 divided by 2 O subscript 2 end subscript left parenthesis g right parenthesis minus (ii) Then,

    Chemistry-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.