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Chemistry-

General

Easy

Question

Following is the graph between $left parenthesis a minus x right parenthesis to the power of negative 1 end exponent$ and time t for second order reaction. $theta equals t a n to the power of negative 1 end exponent invisible function application left parenthesis 1 divided by 2 right parenthesis semicolon O A equals 2 L m o l to the power of negative 1 end exponent$ hence rate at the start of reaction will be:

1.25 $L {m o l}^{- 1} {m i n}^{- 1}$
0.125 mol $L^{- 1} {m i n}^{- 1}$
0.5 mol $L^{- 1} {m i n}^{- 1}$
1.25 mol $L^{- 1} {m i n}^{- 1}$

The correct answer is: 0.5 mol $L to the power of negative 1 end exponent m i n to the power of negative 1 end exponent$

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