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Maths-

General

Easy

Question

if cot $alpha c o t invisible function application beta equals 2$ , then $fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction$ is equal to

$\frac{1}{3}$
$- \frac{1}{3}$
$\frac{1}{2}$
$- \frac{1}{2}$

The correct answer is: $fraction numerator 1 over denominator 3 end fraction$

Given cot $alpha c o t invisible function application beta equals 2. text So end text$
$fraction numerator c o s invisible function application alpha times c o s invisible function application beta over denominator s i n invisible function application alpha times s i n invisible function application beta end fraction equals fraction numerator 2 over denominator 1 end fraction$
$rightwards double arrow fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction equals fraction numerator 1 over denominator 3 end fraction$

Related Questions to study

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

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$text If end text x comma y comma z text are in AP, then end text fraction numerator s i n invisible function application x minus s i n invisible function application z over denominator c o s invisible function application z minus c o s invisible function application x end fraction text is equal to end text$

$text If end text x comma y comma z text are in AP, then end text fraction numerator s i n invisible function application x minus s i n invisible function application z over denominator c o s invisible function application z minus c o s invisible function application x end fraction text is equal to end text$

$s i n invisible function application fraction numerator pi over denominator 9 end fraction s i n invisible function application fraction numerator 2 pi over denominator 9 end fraction s i n invisible function application fraction numerator 4 pi over denominator 9 end fraction s i n invisible function application fraction numerator pi over denominator 3 end fraction text is equal to end text$

$s i n invisible function application fraction numerator pi over denominator 9 end fraction s i n invisible function application fraction numerator 2 pi over denominator 9 end fraction s i n invisible function application fraction numerator 4 pi over denominator 9 end fraction s i n invisible function application fraction numerator pi over denominator 3 end fraction text is equal to end text$

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To determine the half- life of radioactive element, a student plots graph of ln $open vertical bar fraction numerator d N blank left parenthesis t right parenthesis over denominator d t end fraction close vertical bar v e r s u s$ t. Here $fraction numerator d N blank left parenthesis t right parenthesis over denominator d t end fraction$ is the rate of radioactive decay at time t. If the number of radioactive nuclei of this element decreases by a factor of $p$ after 4.16 yr, the value of $p$ is

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In Bohr model of hydrogen atom, the force on the electron depends on the principal quantum number as

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Assertion : All the radioactive elements are ultimately converted in lead.
Reason : All the elements above lead are unstable.

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