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Chemistry-

General

Easy

Question

The electron affinity values (in $k J m o l to the power of negative 1 end exponent$ ) of three halogens $X comma Y$ and $Z$ are respectively – 349, – 333 and – 325. Then $X comma Y$ and $Z$ are respectively

(a) $F_{2}, C l_{2}$ and $B r_{2}$
$C l_{2}, F_{2}$ and $B r_{2}$
(c) $C l_{2}, B r_{2}$ and $F_{2}$
$B r_{2}, C l_{2}$ and $F_{2}$

The correct answer is: $C l subscript 2 end subscript comma F subscript 2 end subscript$ and $B r subscript 2 end subscript$

In IB group all elements are metals.

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