Chemistry-
General
Easy

Question

The formation of the oxide ion O subscript left parenthesis g right parenthesis end subscript superscript 2 minus end superscript requires first an exothermic and then an endothermic step as shown below
O subscript left parenthesis g right parenthesis end subscript plus e to the power of minus end exponent equals O subscript left parenthesis g right parenthesis end subscript superscript minus end superscript capital delta H to the power of 0 end exponent equals negative 142   k J m o l to the power of negative 1 end exponent
O subscript left parenthesis g right parenthesis end subscript superscript minus end superscript plus e to the power of minus end exponent equals O subscript left parenthesis g right parenthesis end subscript superscript 2 minus end superscript capital delta H to the power of 0 end exponent equals 844   k J m o l to the power of negative 1 end exponent This is because

  1. (a) O to the power of minus end exponent ion will tend to resist the addition of another electron  
  2. Oxygen has high electron affinity  
  3. (c) Oxygen is more electronegative   
  4. O to the power of minus end exponention has comparatively larger size than oxygen atom  

The correct answer is: (a) O to the power of minus end exponent ion will tend to resist the addition of another electron


    The addition of second electron in an atom or ion is always endothermic.

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