Chemistry-
General
Easy
Question
The highest excited state that unexcited hydrogen atoms can reach when they are bombarded with 12.2 eV photon is
- n = 1
- n = 2
- n = 3
- n = 4
The correct answer is: n = 3
E1 = -13.6eV
After absorption of 12.2 eV energy
EH = -13.6 + 12.2 = -1.4 eV
Now En = 
\n2 = 
= 9.71
n > 3
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