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Question

The molalfreezing point constant of water is 1.86 K m to the power of negative 1 end exponent, If 342 g of cane sugar (C subscript 12 end subscript H subscript 22 end subscript O subscript 11 end subscript right parenthesisis dissolved in 1000 g of water, the solution will freeze at

  1. negative 1.86 ℃    
  2. 1.86 degree    
  3. negative 3.92 ℃    
  4. 2.42 ℃    

The correct answer is: negative 1.86 ℃


    increment T subscript f end subscript equals fraction numerator 1000 cross times K subscript f end subscript cross times W over denominator M w end fraction
    equals fraction numerator 1000 cross times 1.86 cross times 342 over denominator 100 cross times 342 end fraction equals 1.86
    therefore blank T subscript f end subscript equals 0 minus 1.86 equals negative 1.86 ℃

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