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Chemistry-

General

Easy

Question

The molar solubility (in mol $text litre end text to the power of negative 1 end exponent$ ) of a sparingly soluble salt $M X subscript 4 end subscript$ is The corresponding solubility product $K subscript s p end subscript$ is given by the relation

$S = {(K_{s p} / 128)}^{1 / 4}$
$S = {(218 K_{s p})}^{1 / 4}$
$S = {(256 K_{s p})}^{1 / 5}$
$S = {(K_{s p} / 256)}^{1 / 5}$

The correct answer is: $S equals open parentheses K subscript s p end subscript divided by 256 close parentheses to the power of 1 divided by 5 end exponent$

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parallel

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