Chemistry
Grade-9
Easy
Question
The quantity of Copper (II) oxide reacts with 2.80L of hydrogen at NTP is
- 10 gm
- 15 gm
- 9.1 gm
- 9.95 g
Hint:
1 mole CuO reacts with 1 mole hydrogen.
The correct answer is: 9.95 g
CuO + H2 
Cu + H2O
1 mole CuO reacts with 1 mole hydrogen.
22.4L of hydrogen at NTP reduce CuO = 79.5g
2.80L of hydrogen at NTP will reduce CuO = 22.479.5×2.80g = 9.95g
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