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Chemistry-

General

Easy

Question

The rate constant for the reaction $2 N subscript 2 end subscript O subscript 5 end subscript rightwards arrow 4 N O subscript 2 end subscript plus O subscript 2 end subscript$ Is $3.0 cross times 10 to the power of negative 5 end exponent s to the power of negative 1 end exponent$ . If the rate is $2.40 cross times 10 to the power of negative 5 end exponent blank m o l blank L to the power of negative 1 end exponent s to the power of negative 1 end exponent$ , then the concentration of $N subscript 2 end subscript O subscript 5 end subscript left parenthesis i n blank m o l blank L to the power of negative 1 end exponent right parenthesis$ is

1.4
1.2
0.04
0.8

The correct answer is: 0.8

$2 N subscript 2 end subscript O subscript 5 end subscript left parenthesis g right parenthesis rightwards arrow 4 N O subscript 2 end subscript left parenthesis g right parenthesis plus O subscript 2 end subscript left parenthesis g right parenthesis$
This reaction is a first order reaction
Rate $equals k open square brackets N subscript 2 end subscript O subscript 5 end subscript close square brackets$
$2.40 cross times 10 to the power of negative 5 end exponent equals 3.0 cross times 10 to the power of negative 5 end exponent cross times left square bracket N subscript 2 end subscript O subscript 5 end subscript right square bracket$
or $open square brackets N subscript 2 end subscript O subscript 5 end subscript close square brackets equals 0.8 blank m o l blank L to the power of negative 1 end exponent$

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