Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Chemistry-

General

Easy

Question

The solubility of $A g I$ in $N a I$ solution is less than that in pure water because

$A g I$ forms complex with $N a I$
Of common ion effect
Solubility product of $A g I$ is less
The temperature of the solution decreases

The correct answer is: Of common ion effect

Solubility is decreased due to common ion effect

Related Questions to study

Which of the following pairs constitutes buffer?

Which of the following pairs constitutes buffer?

Chemistry-General

Which one of the following pair shows buffer’s solution?

Which one of the following pair shows buffer’s solution?

Chemistry-General

Aqueous solutions of two acids having same concentrations of common ion $left parenthesis H to the power of plus end exponent right parenthesis$ are called:

Aqueous solutions of two acids having same concentrations of common ion $left parenthesis H to the power of plus end exponent right parenthesis$ are called:

Chemistry-General

parallel

$N subscript 2 end subscript plus 3 H subscript 2 end subscript rightwards harpoon over leftwards harpoon 2 N H subscript 3 end subscript plus h e a t$ . What is the effect of the increase of temperature on the equilibrium of the reaction?

$N subscript 2 end subscript plus 3 H subscript 2 end subscript rightwards harpoon over leftwards harpoon 2 N H subscript 3 end subscript plus h e a t$ . What is the effect of the increase of temperature on the equilibrium of the reaction?

Chemistry-General

In the titration of $N a subscript 2 end subscript C O subscript 3 end subscript blank a n d blank H C l$ , the indicator used is

In the titration of $N a subscript 2 end subscript C O subscript 3 end subscript blank a n d blank H C l$ , the indicator used is

Chemistry-General

1 mole of $H subscript 2 end subscript blank a n d blank 2 blank m o l e s blank o f blank I subscript 2 end subscript$ are taken initially in a 2 L vessel. The number of moles of $H subscript 2 end subscript$ at equilibrium is 0.2. Then, the number of moles of $I subscript 2 end subscript a n d blank H I$ at equilibrium are

1 mole of $H subscript 2 end subscript blank a n d blank 2 blank m o l e s blank o f blank I subscript 2 end subscript$ are taken initially in a 2 L vessel. The number of moles of $H subscript 2 end subscript$ at equilibrium is 0.2. Then, the number of moles of $I subscript 2 end subscript a n d blank H I$ at equilibrium are

Chemistry-General

parallel

For the reaction, $H subscript 2 end subscript open parentheses g close parentheses plus C O subscript 2 end subscript open parentheses g close parentheses rightwards harpoon over leftwards harpoon C O open parentheses g close parentheses plus H subscript 2 end subscript O left parenthesis g right parenthesis$ , if the initial concentration of $open square brackets H subscript 2 end subscript close square brackets equals open square brackets C O subscript 2 end subscript close square brackets a n d x$ mol/L of hydrogen is consumed at equilibrium, the correct expression of $K subscript p end subscript$ is

For the reaction, $H subscript 2 end subscript open parentheses g close parentheses plus C O subscript 2 end subscript open parentheses g close parentheses rightwards harpoon over leftwards harpoon C O open parentheses g close parentheses plus H subscript 2 end subscript O left parenthesis g right parenthesis$ , if the initial concentration of $open square brackets H subscript 2 end subscript close square brackets equals open square brackets C O subscript 2 end subscript close square brackets a n d x$ mol/L of hydrogen is consumed at equilibrium, the correct expression of $K subscript p end subscript$ is

Chemistry-General

Of the following which change will shift the reaction towards the product? $I subscript 2 end subscript open parentheses g close parentheses rightwards harpoon over leftwards harpoon 2 I open parentheses g close parentheses comma blank increment H degree subscript r end subscript open parentheses 298 blank K close parentheses equals plus 150 blank k J$

Of the following which change will shift the reaction towards the product? $I subscript 2 end subscript open parentheses g close parentheses rightwards harpoon over leftwards harpoon 2 I open parentheses g close parentheses comma blank increment H degree subscript r end subscript open parentheses 298 blank K close parentheses equals plus 150 blank k J$

Chemistry-General

$K subscript a end subscript$ forHCN is $5 cross times 10 to the power of negative 10 end exponent$ at $25 ℃$ . For maintaining a constant $p H equals 9$ , the volume of 5 M KCN solution required to be added to 10 mL of 2 M HCN solution is

$K subscript a end subscript$ forHCN is $5 cross times 10 to the power of negative 10 end exponent$ at $25 ℃$ . For maintaining a constant $p H equals 9$ , the volume of 5 M KCN solution required to be added to 10 mL of 2 M HCN solution is

Chemistry-General

parallel

When $C a C O subscript 3 end subscript$ is heated at a constant temperature in a closed container, the pressure due to $C O subscript 2 end subscript$ produced will:

When $C a C O subscript 3 end subscript$ is heated at a constant temperature in a closed container, the pressure due to $C O subscript 2 end subscript$ produced will:

Chemistry-General

Which favours the backward reaction in a chemical equilibrium?

Which favours the backward reaction in a chemical equilibrium?

Chemistry-General

In $K subscript p end subscript equals K subscript c end subscript open square brackets R T close square brackets to the power of increment n end exponent comma increment n$ may have:

In $K subscript p end subscript equals K subscript c end subscript open square brackets R T close square brackets to the power of increment n end exponent comma increment n$ may have:

Chemistry-General

parallel

The $left square bracket H to the power of plus end exponent right square bracket$ ion concentration in $0.001 blank M$ acetic acid is $1.34 cross times 10 to the power of negative 4 end exponent g blank i o n divided by l i t r e.$ The $open square brackets H to the power of plus end exponent close square brackets$ ion concentration of $0.164 g blank o f blank C H subscript 3 end subscript C O O N a$ is added to a $l i t r e$ of $0.001 blank M C H subscript 3 end subscript C O O H$ will be:

The $left square bracket H to the power of plus end exponent right square bracket$ ion concentration in $0.001 blank M$ acetic acid is $1.34 cross times 10 to the power of negative 4 end exponent g blank i o n divided by l i t r e.$ The $open square brackets H to the power of plus end exponent close square brackets$ ion concentration of $0.164 g blank o f blank C H subscript 3 end subscript C O O N a$ is added to a $l i t r e$ of $0.001 blank M C H subscript 3 end subscript C O O H$ will be:

Chemistry-General

Which of the following is a buffer?

Which of the following is a buffer?

Chemistry-General

$M g to the power of 2 plus end exponent$ is … than $A l to the power of 3 plus end exponent$ .

$M g to the power of 2 plus end exponent$ is … than $A l to the power of 3 plus end exponent$ .

Chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.