Chemistry-
General
Easy

Question

The work function (capital phi) of some metals is listed below. The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metals is :

  1. 2    
  2. 4    
  3. 6    
  4. 8    

The correct answer is: 4


    Energy of photonequals fraction numerator h c over denominator lambda end fraction J equals fraction numerator h c over denominator e lambda end fraction e V
    equals fraction numerator 6.625 cross times 10 to the power of negative 34 end exponent cross times 3 cross times 10 to the power of 8 end exponent over denominator 300 cross times 10 to the power of negative 9 end exponent cross times 1.602 cross times 10 to the power of negative 19 end exponent end fraction equals 4.14 blank e V
    For photoelectric effect to occur, energy of incident photons, must be greater than work functions of metal. Hence, only Li, Na, K and Mg have work functions less than 4.14 V.

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