Solution for the question - when co2 dissolves in water the following equilibrium is established,co2+2h2o tau h3o++hco3 for which the equilibrium constant 3.8 t

Chemistry-

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Question

When CO₂ dissolves in water the following equilibrium is established, CO₂ + 2H₂O $rightwards harpoon over leftwards harpoon$ H₃O⁺ + HCO₃^– for which the equilibrium constant 3.8 $rightwards harpoon over leftwards harpoon$ 10^–7 and pH = 6.0. The ratio of $open square brackets H C O subscript 3 close square brackets open square brackets H C O subscript 3 superscript minus close square brackets$ to $open square brackets C O subscript 2 close square brackets$ would be

$3.8 \times 10^{- 18}$
$3.8 \times 10^{- 13}$
13.4
6.0

The correct answer is: $3.8 cross times 10 to the power of negative 18 end exponent$

In $triangle A B C comma a b c sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

Maths-General

General

Maths-

In $capital delta A B C comma a squared c o t invisible function application A plus b squared c o t invisible function application B plus C squared c o t invisible function application C equals$

Maths-General

General

Maths-

In $triangle A B C comma c o t invisible function application A divided by 2 plus c o t invisible function application B divided by 2 plus c o t invisible function application C divided by 2 equals$

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General

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In $capital delta A B C comma c o t invisible function application A plus c o t invisible function application B plus c o t invisible function application C equals$

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General

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In $triangle A B C comma 4 R capital delta sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

Maths-General

General

Maths-

If 'O' is the Orthocentre of $triangle A B C$ then $O A equals$

Maths-General

General

Maths-

In $I n triangle A B C comma sum a cubed c o s invisible function application left parenthesis B minus C right parenthesis equals$

Maths-General

General

Maths-

In $triangle A B C comma left parenthesis a plus b right parenthesis cos invisible function application C plus left parenthesis b plus c right parenthesis cos invisible function application A plus left parenthesis c plus a right parenthesis cos invisible function application B equals$

Maths-General

General

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In $triangle A B C comma sum 1 divided by a c o s squared invisible function application A divided by 2 equals$

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In $triangle A B C comma s squared t a n invisible function application A divided by 2 t a n invisible function application B divided by 2 t a n invisible function application C divided by 2 equals$

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General

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In $triangle A B C comma 4 R s sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

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General

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In $A B C space comma space 4 R cos A divided by 2 space cos B divided by 2 space cos C divided by 2 equals$

Maths-General

General

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In $triangle A B C comma sum a cos invisible function application A equals$

Maths-General

General

Maths-

In $capital delta A B C comma sum left parenthesis left parenthesis b squared minus c squared right parenthesis right parenthesis divided by a c o s invisible function application A equals$

Maths-General

General

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$L t left parenthesis x rightwards arrow pi divided by 6 right parenthesis left parenthesis left parenthesis 3 s i n x minus √ 3 c o s x right parenthesis divided by left parenthesis 6 x minus pi right parenthesis right parenthesis equals$

Maths-General

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When CO2 dissolves in water the following equilibrium is established, CO2 + 2H2O H3O+ + HCO3– for which the equilibrium constant 3.8 10–7 and pH = 6.0. The ratio of to would be

13.4 6.0

The correct answer is:

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$3.8 \times 10^{- 18}$
$3.8 \times 10^{- 13}$
13.4
6.0

The correct answer is: $3.8 cross times 10 to the power of negative 18 end exponent$

In $triangle A B C comma a b c sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

In $triangle A B C comma a b c sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

In $capital delta A B C comma a squared c o t invisible function application A plus b squared c o t invisible function application B plus C squared c o t invisible function application C equals$

In $capital delta A B C comma a squared c o t invisible function application A plus b squared c o t invisible function application B plus C squared c o t invisible function application C equals$

In $triangle A B C comma c o t invisible function application A divided by 2 plus c o t invisible function application B divided by 2 plus c o t invisible function application C divided by 2 equals$

In $triangle A B C comma c o t invisible function application A divided by 2 plus c o t invisible function application B divided by 2 plus c o t invisible function application C divided by 2 equals$

In $capital delta A B C comma c o t invisible function application A plus c o t invisible function application B plus c o t invisible function application C equals$

In $capital delta A B C comma c o t invisible function application A plus c o t invisible function application B plus c o t invisible function application C equals$

In $triangle A B C comma 4 R capital delta sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

In $triangle A B C comma 4 R capital delta sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

If 'O' is the Orthocentre of $triangle A B C$ then $O A equals$

If 'O' is the Orthocentre of $triangle A B C$ then $O A equals$

In $I n triangle A B C comma sum a cubed c o s invisible function application left parenthesis B minus C right parenthesis equals$

In $I n triangle A B C comma sum a cubed c o s invisible function application left parenthesis B minus C right parenthesis equals$

In $triangle A B C comma left parenthesis a plus b right parenthesis cos invisible function application C plus left parenthesis b plus c right parenthesis cos invisible function application A plus left parenthesis c plus a right parenthesis cos invisible function application B equals$

In $triangle A B C comma left parenthesis a plus b right parenthesis cos invisible function application C plus left parenthesis b plus c right parenthesis cos invisible function application A plus left parenthesis c plus a right parenthesis cos invisible function application B equals$

In $triangle A B C comma sum 1 divided by a c o s squared invisible function application A divided by 2 equals$

In $triangle A B C comma sum 1 divided by a c o s squared invisible function application A divided by 2 equals$

In $triangle A B C comma s squared t a n invisible function application A divided by 2 t a n invisible function application B divided by 2 t a n invisible function application C divided by 2 equals$

In $triangle A B C comma s squared t a n invisible function application A divided by 2 t a n invisible function application B divided by 2 t a n invisible function application C divided by 2 equals$

In $triangle A B C comma 4 R s sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

In $triangle A B C comma 4 R s sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals$

In $A B C space comma space 4 R cos A divided by 2 space cos B divided by 2 space cos C divided by 2 equals$

In $A B C space comma space 4 R cos A divided by 2 space cos B divided by 2 space cos C divided by 2 equals$

In $triangle A B C comma sum a cos invisible function application A equals$

In $triangle A B C comma sum a cos invisible function application A equals$

In $capital delta A B C comma sum left parenthesis left parenthesis b squared minus c squared right parenthesis right parenthesis divided by a c o s invisible function application A equals$

In $capital delta A B C comma sum left parenthesis left parenthesis b squared minus c squared right parenthesis right parenthesis divided by a c o s invisible function application A equals$