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Chemistry-

General

Easy

Question

Which reagent is used for the conversion of (A) to (B) ?

$H_{2} + [R h C l {(P h_{3} P)}_{3}]$
$N H_{2} N H_{2} + O_{2}$
$M M P P i n e t h a n o l / H_{3} O^{\oplus}$
$S i a_{2} B H + C H_{3} C O O H$

The correct answer is: $S i a subscript 2 end subscript B H plus C H subscript 3 end subscript C O O H$

And (b) reduce both the $left parenthesis C equals C right parenthesis$ to $open parentheses C minus C close parentheses$ (sys-addition)
Anti-hydroxylation of both $left parenthesis C equals C right parenthesis$ to
Reduces only unhindered $open parentheses C equals C close parentheses$ to $left parenthesis C minus C right parenthesis$

Related Questions to study

The Area of the region between x-y+2=0 and the curve x = $blank square root of y blank$ is…

The Area of the region between x-y+2=0 and the curve x = $blank square root of y blank$ is…

$T h e blank a r e a blank l y i n g blank i n blank t h e blank f i r s t blank q u a d r a n t blank b e t w e e n blank t h e blank c u r v e s blank x to the power of 2 end exponent plus y to the power of 2 end exponent equals pi to the power of 2 end exponent blank a n d blank y equals s i n blank x blank a n d blank y minus a x i s blank i s$

$T h e blank a r e a blank l y i n g blank i n blank t h e blank f i r s t blank q u a d r a n t blank b e t w e e n blank t h e blank c u r v e s blank x to the power of 2 end exponent plus y to the power of 2 end exponent equals pi to the power of 2 end exponent blank a n d blank y equals s i n blank x blank a n d blank y minus a x i s blank i s$

$T h e blank a r e a blank c o m m o n blank t o blank t h e blank c i r c l e blank x to the power of 2 end exponent plus y to the power of 2 end exponent equals 16 a to the power of 2 end exponent blank a n d blank y to the power of 2 end exponent equals 6 a x blank i s$

$T h e blank a r e a blank c o m m o n blank t o blank t h e blank c i r c l e blank x to the power of 2 end exponent plus y to the power of 2 end exponent equals 16 a to the power of 2 end exponent blank a n d blank y to the power of 2 end exponent equals 6 a x blank i s$

parallel

$I n blank a blank t r i a n g l e A B C blank comma blank i f blank open parentheses 1 plus fraction numerator a over denominator b end fraction plus fraction numerator c over denominator b end fraction close parentheses open parentheses 1 plus fraction numerator b over denominator c end fraction minus fraction numerator a over denominator c end fraction close parentheses equals 3 blank comma blank t h e n blank t h e blank a n g l e blank A$ is equal to

$I n blank a blank t r i a n g l e A B C blank comma blank i f blank open parentheses 1 plus fraction numerator a over denominator b end fraction plus fraction numerator c over denominator b end fraction close parentheses open parentheses 1 plus fraction numerator b over denominator c end fraction minus fraction numerator a over denominator c end fraction close parentheses equals 3 blank comma blank t h e n blank t h e blank a n g l e blank A$ is equal to

(A) is:

(A) is:

Chemistry-General

Which statement is correct about the following reaction?

Which statement is correct about the following reaction?

Chemistry-General

parallel

Reagent I and II, respectively are :

Reagent I and II, respectively are :

Chemistry-General

Compound (B) is:

Compound (B) is:

Chemistry-General

The range of the function $s i n invisible function application left parenthesis left square bracket x right square bracket pi right parenthesis$ is

The range of the function $s i n invisible function application left parenthesis left square bracket x right square bracket pi right parenthesis$ is

parallel

The domain of the function $f left parenthesis x right parenthesis equals square root of l o g invisible function application fraction numerator 1 over denominator vertical line s i n invisible function application x vertical line end fraction end root$ is

The domain of the function $f left parenthesis x right parenthesis equals square root of l o g invisible function application fraction numerator 1 over denominator vertical line s i n invisible function application x vertical line end fraction end root$ is

$T h e blank a r e a blank i n blank t h e blank f i r s t blank q u a d r a n t blank e n c l o s e d blank b y blank t h e blank X minus a x i s blank u n d e r blank t h e blank c u r v e blank x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4 blank a n d blank t h e blank l i n e blank x equals fraction numerator y over denominator square root of 3 end fraction i s blank$

$T h e blank a r e a blank i n blank t h e blank f i r s t blank q u a d r a n t blank e n c l o s e d blank b y blank t h e blank X minus a x i s blank u n d e r blank t h e blank c u r v e blank x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4 blank a n d blank t h e blank l i n e blank x equals fraction numerator y over denominator square root of 3 end fraction i s blank$

Which of the following reactions is Hofmann elimination?
I)
II)
III)
IV)

Which of the following reactions is Hofmann elimination?
I)
II)
III)
IV)

Chemistry-General

parallel

The decreasing order of reactivity towards $A r S N$ reaction of the following with $N a O M e$ is:
I)
II)
III)
IV)

The decreasing order of reactivity towards $A r S N$ reaction of the following with $N a O M e$ is:
I)
II)
III)
IV)

Chemistry-General

Which product is racemic in the above reaction?

Which product is racemic in the above reaction?

Chemistry-General

$A r e a blank o f blank t h e blank s e g m e n t blank c u t blank o f f blank f r o m blank t h e blank p a r a b o l a blank x to the power of 2 end exponent equals 8 y blank b y blank t h e blank l i n e blank x minus 2 y plus 8 equals 0 blank i s$

$A r e a blank o f blank t h e blank s e g m e n t blank c u t blank o f f blank f r o m blank t h e blank p a r a b o l a blank x to the power of 2 end exponent equals 8 y blank b y blank t h e blank l i n e blank x minus 2 y plus 8 equals 0 blank i s$

parallel

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