convert the mixed fractions into improper fractions. Then follow BODMAS rule. We get ((7 x7)+ 1)/7 + 1/7 = 50/7 + 1/7 = 51/7 . Now, let’s multiply 51/7 x 1/7, we get 51/49

convert the mixed fractions into improper fractions. Then follow BODMAS rule. We get ((5 x1)+ 2)/5 + 7/3 = 26/15 . Now, let’s multiply 26/15 x 7/13, we get 14/15

Let’s convert the mixed fractions into improper fractions. We get ((5 x 1) +2)/5 and 2/3, i.e., 7/5 and 2/3. Let’s calculate the product 7/5 x 2/3 we get 14/15

Follow the BODMAS rule. So, first let’s add 1/7 and 1/3, we get 9/14. Now , convert the mixed fraction into improper fraction, we get 9/2. Multiplying 9/14 x 9/2 , we get 81/28. This isn’t given in any of the options, so, answer is none of the above.

Let’s convert the mixed fractions into improper fractions. We get 2/15 and ((2 x 1) + 1)/2, i.e., 2/15 and 3/2. Let’s calculate the product 2/15 x 3/2 we get 1/5

Compare using >, <, or =
.

Let’s convert the mixed fractions into improper fractions. We get 2/2 and ((3 x 1) + 1)/3, i.e., 2/2 and 4/3. Let’s calculate the product 2/2  x 4/3 we get 4/3

Let’s convert the mixed fractions into improper fractions. We get ((20 x 1) +1)/20 and 1/7 i.e., 21/20 and 1/7. Let’s calculate the product 21/20 x 1/7 we get 3/20

Anything multiplied by 0 is 0. Hence, the answer is 0.

Let’s convert the mixed fractions into improper fractions. We get ((5 x 3) +1)/5 and 10/2, i.e., 16/5 and 10/2. Let’s calculate the product 16/5 x 10/5 we get 16

Lets convert the mixed fractions into improper fractions. We get ((9 x 1) +1)/9 and ((3 x 2)+ 1)/3, i.e., 10/9 and7/3. Let’s calculate the product 10/9 x 7/3 we get 70/27

Lets convert the mixed fractions into improper fractions. We get ((2 x 4) +1)/2 and 1/2 i.e., 9/2 and 1/2. Let’s calculate the product 9/2 x 1/2 we get 9/4

Lets convert the mixed fractions into improper fractions. We get ((9 x 3) +3)/9 and ((3 x 1)+ 1)/3, i.e., 30/9 and 4/3. Let’s calculate the product 30/9 x 4/3 . we get 40/9

Mark has a rectangular doormat on her porch. The mat is  m long and  m wide. What is the area of   the doormat?

Given, length = 4/5 m and breath =1/2 m. Let’s find out the product of the 2 dimensions given. We get 1/2 x 4/5 = 2/5 sq. m, which is the required answer.

Steven calculated the area of a square to be square yard. What is the side length of the square?

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Given, area of square = 1/81 sq yard. This means that the square of side length is 1/ 81. This means that we need to find the square root of 1/ 81. Square root of 1 is 1.  To find the square root of 81, let’s find the factors of 81.  By using hit and trial method, we can write that 81 = 3 x 3 x 3 x3 = 9 x 9. Hence, 9 is the square root of 81. Hence, our required answer is 1/9 , which is the square root of 1/81.