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Mathematics

Grade6

Easy

Question

$fraction numerator 6 over denominator 13 end fraction$ multiplied by reciprocal of $fraction numerator 7 over denominator 16 end fraction$ is___________.

$\frac{91}{96}$
$\frac{96}{91}$
$\frac{9}{7}$
$\frac{7}{9}$

The correct answer is: $fraction numerator 96 over denominator 91 end fraction$

We will first find the reciprocal of $7 over 16$ , which is equal to $16 over 7$
Now we will do multiplication
$6 over 13 cross times 16 over 7 equals 96 over 91$

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