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Mathematics

Grade6

Easy

Question

A rectangular sheet of paper is $fraction numerator 63 over denominator 4 end fraction$ cm long having area $fraction numerator 130 over denominator 2 end fraction c m to the power of 2 end exponent$ , then what is its width?

$\frac{420}{126}$ cm
$\frac{42}{16}$ cm
$\frac{520}{126}$ cm
$\frac{163}{520}$

hint Hint:

Area of the rectangle is $l cross times b$ .

The correct answer is: $fraction numerator 520 over denominator 126 end fraction$ cm

Area of rectangle = $l cross times b$ = $fraction numerator 130 over denominator 2 end fraction c m to the power of 2 end exponent$
Breadth of rectangle (B) = $fraction numerator a r e a over denominator l e n g t h end fraction$
$equals fraction numerator 130 over denominator 2 end fraction divided by fraction numerator 63 over denominator 4 end fraction equals fraction numerator 130 over denominator 2 end fraction cross times fraction numerator 4 over denominator 63 end fraction equals fraction numerator 520 over denominator 126 end fraction$ cm

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