Mathematics
Grade-8
Easy

Question

A spherical ball has a radius of 2 inches. The ball has a slow leak which the air escapes at a rate of 1 cubic inches per second. The time it would take for the ball to deflate is ___________.

  1. 10.6 s
  2. 41 s
  3. 33.5 s
  4. 14.2 s

hintHint:

Here, in this problem, we want to calculate the time required to deflate the spherical ball whose radius is given. Obviously, the total time required will be the volume of the air inside the ball divided by the rate of escaping of the air through the leak from the ball. Now, the total volume of air inside the ball is the same as the volume of the given spherical ball. For this, we have to use the formula for calculating the volume of a sphere. The volume V  of a sphere of radius r is given by the formula, V equals 4 over 3 straight pi r cubed.

The correct answer is: 33.5 s


    Given that the radius of the spherical ball is r equals 2 inches.
    We have to find the total volume of the air inside the ball. Now, the volume of the air will be the same as the volume of the spherical ball. Now, the volume V of a spherical ball of radius r is V equals 4 over 3 straight pi r cubed.
    So, for r equals 2 inches, we get: V equals 4 over 3 cross times straight pi cross times 2 cubed equals 33.5 space text in end text cubed.
    Hence, the volume of the air is 33.5 space text in end text cubed.
    Now, the rate at which the air is escaping through a slow leak is e equals 1 space text in end text cubed text /sec end text.
    So, the time required to deflate the ball is t equals V over e equals fraction numerator 33.5 over denominator 1 end fraction equals 33.5 space text sec end text.
    Therefore, the time it would take for the ball to deflate is 33.5 space text sec end text.

    Note that, here, we can use 3.14 space text or end text space 22 over 7 in the place of straight pi to find the volume of the given spherical ball using the formula V equals 4 over 3 straight pi r cubed.

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