Mathematics
Grade9
Easy

Question

A square pyramid is covered with decorative wrapping paper with no overlap. The net of the box is shown on the right. How many square centimeters of wrapping paper are needed to cover the surfaces of the box?

  1. 108 space cm squared
  2. 324 space cm squared
  3. 180 space cm squared
  4. 432 space cm squared

hintHint:

The surface area of Pyramid = B space plus space 1 half space cross times space P l space where p is the perimeter of the base , B is area of the base and l is the slant height of the pyramid.

The correct answer is: 180 space cm squared


    This net forms a pyramid with base as it has a square base and 4 triangles as the side surfaces.  text  The perimeter of base = 4 x 6 = 24 cm end text
text The area of the base is  end text 6 squared equals 36 space c m squared
text  Use the surface area formula,  end text
text  Surface area  end text equals B plus 1 half cross times Pl
S. A space equals space 36 space plus space 1 half space left parenthesis 24 right parenthesis left parenthesis 12 right parenthesis
equals 180 space cm squared
    Therefore,180 square centimeters of wrapping paper are needed to cover the surfaces of the box.

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