Mathematics

Grade9

Easy

Question

Add the matrices: $open square brackets table row 0 3 row 2 4 end table close square brackets comma space open square brackets table row 1 3 row 5 2 end table close square brackets$

$[\begin{array}{l} 1 & 6 \\ 7 & 6 \end{array}]$
$[\begin{array}{l} 1 & 4 \\ 7 & 3 \end{array}]$
$[\begin{array}{l} 8 & 6 \\ 7 & 6 \end{array}]$
$[\begin{array}{l} 0 & 5 \\ 7 & 6 \end{array}]$

hint Hint:

Two or more matrices of the same order can be added by adding the corresponding elements of the matrices.
If A = [aij] and B = [bij] are two matrices with the same dimension, that is, they have the same number of rows and columns, then the addition of matrices A and B is: A+B = [aij] + [bij] = [aij + bij], here ij denotes the position of each element in i^th row and j^th column.

The correct answer is: $open square brackets table attributes columnalign left end attributes row 1 6 row 7 6 end table close square brackets$

Two or more matrices of the same order can be added by adding the corresponding elements of the matrices.
If A = [aij] and B = [bij] are two matrices with the same dimension, that is, they have the same number of rows and columns, then the addition of matrices A and B is: A+B = [aij] + [bij] = [aij + bij], here ij denotes the position of each element in ith row and jth column.
$A space equals space open square brackets table row cell a 11 end cell cell a 12 end cell row cell a 21 end cell cell a 22 end cell end table close square brackets space a n d space B space equals space open square brackets table row cell b 11 end cell cell b 12 end cell row cell b 21 end cell cell b 22 end cell end table close square brackets A space plus space B space equals space open square brackets table row cell a 11 space plus space b 11 end cell cell a 12 space plus space b 12 end cell row cell a 21 space plus space b 21 end cell cell a 22 space plus space b 22 end cell end table close square brackets$
$A space equals space open square brackets table row 0 3 row 2 4 end table close square brackets comma B space equals space space open square brackets table row 1 3 row 5 2 end table close square brackets$
$A space plus space B space equals open square brackets table attributes columnalign left end attributes row 0 3 row 2 4 end table close square brackets plus open square brackets table attributes columnalign left end attributes row 1 3 row 5 2 end table close square brackets equals open square brackets table attributes columnalign left end attributes row cell 0 plus 1 end cell cell 3 space plus space 3 end cell row cell 2 space plus space 5 end cell cell 4 space plus space 2 end cell end table close square brackets space equals space open square brackets table row 1 6 row 7 6 end table close square brackets$

Add the matrices: $A equals open square brackets table attributes columnalign left end attributes row 1 2 end table close square brackets comma space B equals open square brackets table attributes columnalign left end attributes row 3 4 end table close square brackets$

MathematicsGrade9

Grade9

Mathematics

Name the vector.

MathematicsGrade9

Grade9

Mathematics

What will be the new position of the given point after translation of 3 units up and 3 units right?

MathematicsGrade9

Grade9

Mathematics

$open square brackets table row cell negative 9 end cell 12 row 5 cell negative 4 end cell end table close square brackets plus open square brackets table row 20 18 row 11 25 end table close square brackets$ =

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

The pre-image of B(-1, 5) if translation is (x, y) $rightwards arrow$ (x – 8, y + 4) is

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

Translate M(-3, 0) using the vector $left angle bracket 2 comma negative 6 right angle bracket$ .

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

Translate M(5, 3) using the vector $left angle bracket minus 2 comma 6 right angle bracket$ .

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

$open square brackets table row 3 cell negative 8 end cell row 9 cell 4.3 end cell end table close square brackets plus open square brackets table row cell negative 10 end cell 2 row cell 5.1 end cell cell negative 5 end cell end table close square brackets equals$

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

The image of H(-4, 5) after the glide reflection.
Translation: (x, y) $rightwards arrow$ (x – 4, y – 5)
Reflection: y = x

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

The image matrix that represents the 90^o rotation of ABCD about the origin if polygon matrix for ABCD is $open square brackets table attributes columnalign left end attributes row cell negative 2 end cell 1 2 cell negative 3 end cell row 4 4 2 2 end table close square brackets$ is

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

In the diagram, the center of the dilation of PQRS is point C. The length of a side of P^lQ^lR^lS^l is ____ percent of the length of the corresponding side of PQRS.

9th-Grade-Math---USAProperties-of-Transformations

Properties-of-Transformations

9th-Grade-Math---USA

$negative 2 open square brackets table row cell negative 4 end cell 1 0 row 9 cell negative 5 end cell cell negative 7 end cell end table close square brackets$ =

9th-Grade-Math---USAProperties-of-Transformations

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Related Questions to study

Add the matrices:

Add the matrices:

Name the vector.

Name the vector.

What will be the new position of the given point after translation of 3 units up and 3 units right?

What will be the new position of the given point after translation of 3 units up and 3 units right?

Name the vector.

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Write the vector component form.

Write the vector component form.

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=

=

The pre-image of B(-1, 5) if translation is (x, y)(x – 8, y + 4) is

The pre-image of B(-1, 5) if translation is (x, y)(x – 8, y + 4) is

Translate M(-3, 0) using the vector.

Translate M(-3, 0) using the vector.

Translate M(5, 3) using the vector .

Translate M(5, 3) using the vector .

The image of H(-4, 5) after the glide reflection.Translation: (x, y)(x – 4, y – 5)Reflection: y = x

The image of H(-4, 5) after the glide reflection.Translation: (x, y)(x – 4, y – 5)Reflection: y = x

The image matrix that represents the 90o rotation of ABCD about the origin if polygon matrix for ABCD is is

The image matrix that represents the 90o rotation of ABCD about the origin if polygon matrix for ABCD is is

In the diagram, the center of the dilation of PQRS is point C. The length of a side of PlQlRlSl is ____ percent of the length of the corresponding side of PQRS.

In the diagram, the center of the dilation of PQRS is point C. The length of a side of PlQlRlSl is ____ percent of the length of the corresponding side of PQRS.

=

=

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Add the matrices: $open square brackets table row 0 3 row 2 4 end table close square brackets comma space open square brackets table row 1 3 row 5 2 end table close square brackets$

The correct answer is: $open square brackets table attributes columnalign left end attributes row 1 6 row 7 6 end table close square brackets$

Add the matrices: $A equals open square brackets table attributes columnalign left end attributes row 1 2 end table close square brackets comma space B equals open square brackets table attributes columnalign left end attributes row 3 4 end table close square brackets$

Add the matrices: $A equals open square brackets table attributes columnalign left end attributes row 1 2 end table close square brackets comma space B equals open square brackets table attributes columnalign left end attributes row 3 4 end table close square brackets$

$open square brackets table row cell negative 9 end cell 12 row 5 cell negative 4 end cell end table close square brackets plus open square brackets table row 20 18 row 11 25 end table close square brackets$ =

$open square brackets table row cell negative 9 end cell 12 row 5 cell negative 4 end cell end table close square brackets plus open square brackets table row 20 18 row 11 25 end table close square brackets$ =

The pre-image of B(-1, 5) if translation is (x, y) $rightwards arrow$ (x – 8, y + 4) is

The pre-image of B(-1, 5) if translation is (x, y) $rightwards arrow$ (x – 8, y + 4) is

Translate M(-3, 0) using the vector $left angle bracket 2 comma negative 6 right angle bracket$ .

Translate M(-3, 0) using the vector $left angle bracket 2 comma negative 6 right angle bracket$ .

Translate M(5, 3) using the vector $left angle bracket minus 2 comma 6 right angle bracket$ .

Translate M(5, 3) using the vector $left angle bracket minus 2 comma 6 right angle bracket$ .

The image of H(-4, 5) after the glide reflection.
Translation: (x, y) $rightwards arrow$ (x – 4, y – 5)
Reflection: y = x

The image of H(-4, 5) after the glide reflection.
Translation: (x, y) $rightwards arrow$ (x – 4, y – 5)
Reflection: y = x

The image matrix that represents the 90^o rotation of ABCD about the origin if polygon matrix for ABCD is $open square brackets table attributes columnalign left end attributes row cell negative 2 end cell 1 2 cell negative 3 end cell row 4 4 2 2 end table close square brackets$ is

The image matrix that represents the 90^o rotation of ABCD about the origin if polygon matrix for ABCD is $open square brackets table attributes columnalign left end attributes row cell negative 2 end cell 1 2 cell negative 3 end cell row 4 4 2 2 end table close square brackets$ is

In the diagram, the center of the dilation of PQRS is point C. The length of a side of P^lQ^lR^lS^l is ____ percent of the length of the corresponding side of PQRS.

In the diagram, the center of the dilation of PQRS is point C. The length of a side of P^lQ^lR^lS^l is ____ percent of the length of the corresponding side of PQRS.

$negative 2 open square brackets table row cell negative 4 end cell 1 0 row 9 cell negative 5 end cell cell negative 7 end cell end table close square brackets$ =

$negative 2 open square brackets table row cell negative 4 end cell 1 0 row 9 cell negative 5 end cell cell negative 7 end cell end table close square brackets$ =