Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Mathematics

Grade6

Easy

Question

An oil tin contains $fraction numerator 17 over denominator 2 end fraction$ liters of oil which is poured into $fraction numerator 3 over denominator 2 end fraction$ liters bottles. How many bottles are required to fill $fraction numerator 17 over denominator 2 end fraction$ liters of oil?

$\frac{3}{17}$
$\frac{17}{3}$
$\frac{51}{6}$
$\frac{1}{6}$

hint Hint:

For dividing two fraction, we use reciprocal method.

The correct answer is: $fraction numerator 17 over denominator 3 end fraction$

We have given total volume of oil $17 over 2$ litres
The number of bottles required $equals fraction numerator 17 over denominator 2 end fraction divided by fraction numerator 3 over denominator 2 end fraction$
$equals fraction numerator 17 over denominator 2 end fraction cross times fraction numerator 2 over denominator 3 end fraction open parentheses text reciprocal of end text fraction numerator 3 over denominator 2 end fraction text is end text fraction numerator 2 over denominator 3 end fraction close parentheses$
$equals fraction numerator 17 cross times 2 over denominator 2 cross times 3 end fraction equals 17 over 3 almost equal to 5.666$
We know that the number of bottles can't be decimal.
So, The number of bottle require will be 6.

Related Questions to study

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.