Mathematics
Grade10
Easy

Question

Find the area of the right-angled triangle if the height is 11 units and the base is x units, given that the area of the triangle lies between 17 and 42 sq. units

  1. 17 less than fraction numerator 11 x over denominator 2 end fraction less than 42  
  2. A > 17
  3. A ≤ 42
  4. 17 ≤ 11x ≤ 42

hintHint:

The height of a right-angled triangle is 11 units. The base of a right-angled triangle is x units. We have to find the area of the right-angled triangle. We are given limits for the area. The area should lie between 17 sq. units and 42 sq. units. We have to write the given data in mathematical form.

The correct answer is: 17 less than fraction numerator 11 x over denominator 2 end fraction less than 42


    The height of the right-angled triangle is 11 units.
    The base of the right-angled triangle is x units.
    The area lies between the 17sq. units and 42sq. units. So, this question is of inequality. We have to write the mathematical form of this inequality.
    The area of a right-angled triangle is given as follows:
    Area = 1 half cross times 11 cross times x
    equals fraction numerator 11 x over denominator 2 end fraction
    Now, we will see the limits.
    The area lies between 17sq. units and 42sq. units.
    It means the area should be greater than 17sq. units and less than 42sq. units.
    So, we can write
    17 < Area < 42
    17 less than fraction numerator 11 x over denominator 2 end fraction less than 42
    Tbis is the given inequality.

    For such questions, we should check the limits of the inequality. We should check the upper limit and lower limit.

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