Mathematics
Grade9
Easy

Question

Find the values of k such that the points (-10,8),(k, k), (-k, -7) are collinear.

  1. 33 and 70
  2. 35 and -2
  3. 16 and -27
  4. 14 and 3

hintHint:

In this question, we have to find the value of k if the points A(-10,8), B(k, k), C(-k, -7) are collinear. Firstly we will calculate the slopes of line AB and AC, as the points are collinear so the slopes of the lines will be equal. So, by equating the slopes of AB and AC we will the required value of the k.

The correct answer is: 35 and -2


    Let the co- ordinates of the collinear points are A(-10,8), B(k, k) and C(-k, -7).
    So, the slope of AB
    equals fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
equals fraction numerator k minus 8 over denominator k minus left parenthesis negative 10 right parenthesis end fraction
equals fraction numerator k minus 8 over denominator k plus 10 end fraction
    Slope of line AC
    equals fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
equals fraction numerator negative 7 minus 8 over denominator negative k minus left parenthesis negative 10 right parenthesis end fraction
equals fraction numerator negative 15 over denominator negative k plus 10 end fraction
    As the points are collinear
    So, the slope of AB = the slope of AC
    fraction numerator k minus 8 over denominator k plus 10 end fraction equals fraction numerator negative 15 over denominator negative k plus 10 end fraction
left parenthesis k minus 8 right parenthesis left parenthesis negative k plus 10 right parenthesis equals left parenthesis negative 15 right parenthesis left parenthesis k plus 10 right parenthesis
minus k squared plus 8 k plus 10 k minus 80 equals negative 15 k minus 150
k squared minus 33 k minus 70 equals 0
k squared minus 35 k plus 2 k minus 70 equals 0
k left parenthesis k minus 35 right parenthesis plus 2 left parenthesis k minus 35 right parenthesis equals 0
left parenthesis k minus 35 right parenthesis left parenthesis k plus 2 right parenthesis equals 0
k equals 35 space o r space k equals negative 2
    So, required value of k is 35 and -2.

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